In the question, there are certain information's that are of immense importance in regards to finding the answer. The first information is that Jose Rivera had purchased 7 textbooks for his classes at River Run Community College. The price that Jose Rivera had to pay was $208.55. The average cost per textbook needs to be found.
The cost of 7 textbooks purchased by Jose Rivera = 208.55 dollars
Then
The cost of 1 textbook purchased by Jose Rivera = (208.55/7) dollars
= 29.79 dollars
The average cost of a textbook purchased by Jose Rivera rounded to the nearest cent is 29.80 dollars.
The trick to calculating the area here is to subdivide the diagram into smaller parts. For example, there's a 3 cm-by-3cm square. The rectangle is 4 cm by 8 cm.. The triangle has a base of 5 cm and a height of 3 cm.
Total area = area of square + area of rectangle + area of triangle
= 9 cm^2 + 32 cm^2 + (1/2)(5 cm)(3 cm)
= (9 + 32 + 7.5) cm^2
= 48.5 cm^2 (total area of figure)
Lynda had 53 fewer fish then jack did
Answer:
a = 6, b = 8, and c = 10.
Step-by-step explanation:
You can easily use the Pythagorean Theorem to solve all of these.
a = 4; b = 6; c = 8... 4^2 + 6^2 = 16 + 36 = 52. 8^2 = 64. 52 is not equal to 64, so the first choice is not a right triangle.
a = 6; b = 8; c = 10... Well this is a multiple of the 3-4-5 Pythagorean triple, so this is a right triangle.
a = 5; b = 6; c = 761... 5^2 + 6^2 = 25 + 36 = 61. 761^2 = 579121, which is not equal to 61, so the third choice is not a right triangle.
a = 6; b = 9; c = 12... 6^2 + 9^2 = 36 + 81 = 117. 12^2 = 144, which is not equal to 117, so the fourth choice is not a right triangle.
The only case where there is a right triangle is the second choice, where a = 6, b = 8, and c = 10.
Hope this helps!
