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1 year ago

Jan has $30. Brenda has $66. How many DVDs can they buy with their total amount if one DVD costs $12?

Mathematics

2 answers:

boyakko [2]1 year ago

7 0

Answer: they can buy about 8 dvds

Step-by-step explanation:

this is because 30 + 66 = 96 and if you do 96 divided by 12 it gives you 8

sergeinik [125]1 year ago

5 0

I think 7 i may be wrong tho sorry!

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Simplify 〖3m〗^8 n^3÷(〖3m〗^8 n^3 )^0

vovangra [49]

$6561m^{8}n^{3}$

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3 years ago

When a data set is normally distributed, about how much of the data fall within one standard deviation of the mean?

Bezzdna [24]

That would be 68% answer

6 0

3 years ago

3<br>Find the value of a <br>in the equation,(3+4√3)(2-a√3)=-18+2√3

ankoles [38]

Given:

The equation is:

$\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}$

To find:

The value of a.

Solution:

We have,

$\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}$

On simplification, we get

$(3)(2)+(4\sqrt{3})(2)+(3)(-a\sqrt{3})+(4\sqrt{3})(-a\sqrt{3})=-18+2\sqrt{3}$

$6+8\sqrt{3}-3a\sqrt{3}-4a(3)=-18+2\sqrt{3}$

$6+8\sqrt{3}-3a\sqrt{3}-12a=-18+2\sqrt{3}$

$(6-12a)+(8-3a)\sqrt{3}=-18+2\sqrt{3}$

On comparing both sides, we get

$6-12a=-18$

$-12a=-18-6$

$a=\dfrac{-24}{-12}$

$a=2$

And,

$8-3a=2$

$-3a=2-8$

$a=\dfrac{-6}{-3}$

$a=2$

Therefore, the value of a is 2.

3 0

2 years ago

The market and Stock J have the following probability distributions:

denis-greek [22]

Answer:

1) $E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

2) $E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

3) $E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

4) $E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

Step-by-step explanation:

For this case we have the following distributions given:

Probability M J

0.3 14% 22%

0.4 10% 4%

0.3 19% 12%

Part 1

The expected value is given by this formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

Part 2

$E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

Part 3

We can calculate the second moment first with the following formula:

$E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

Part 4

We can calculate the second moment first with the following formula:

$E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

8 0

3 years ago

Please help!!!

Likurg_2 [28]

Answer: Hello! I believe your answer would be 162.

Step-by-step explanation: So the formula for Area on a rectangle is WxL. So length will be 9. But if you notice on the scale rectangle the width is the length times two. So the length on the real garden is 18.

6 0

3 years ago