There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
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Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
Answer:
Your blocking people that need help
Step-by-step explanation:
Don’t add posts like these as others who need help will have to go through these first
3.95*10^9 move the decimal to the left untill it is in between the last ans 2nd to last number
Answer:
46.6 ft/sec (to the nearest tenth)
Step-by-step explanation:
There's a common identity useful here: 60 mph = 88 ft/sec.
Mult. 31.8 mph by the conversion factor (88 ft/sec) / (60 mph), obtaining:
46.64 ft/sec.
Only the first one.
A is the answer.
ABC and DEF are similar, A is to D, B is to E, and C is to F. match the corresponding letters.
