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Marina86 [1]
1 year ago
13

If a translation maps point A(-3,1) to point A′(5,5), the translation is:

Mathematics
1 answer:
elena-s [515]1 year ago
6 0

Answer:

D is the correct answer -3+8=5 ,1+4=5

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There are 12 months in a yr so 12/3=4 then 1/3x4=4/3 so 1ft and 1/3 erode each yr. C is the correct answer<span />
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3 years ago
HELP PLEASE ILL GIVE YOU 15 POINTS THANK YOU
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Find the number C(10,6)
EastWind [94]

Answer:

210.

Step-by-step explanation:

Combination formula is

nCr = \frac{n!}{r!(n-r)!}

Then, we have that n = 10 and r=6:

C(10,6) = \frac{10!}{6!(10-6)!}

C(10,6) = \frac{10!}{6!4!}

To simplify calculus, we are going to use that n! = (n-1)!n = (n-2)!(n-1)n and so on.

C(10,6) = \frac{6!*7*8*9*10}{6!4!}

C(10,6) = \frac{7*8*9*10}{4!}

C(10,6) = \frac{5040}{4*3*2*1}

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5 0
2 years ago
Axis of sym: x =
marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

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let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

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