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1 year ago

Find the value of Theta in these diagrams (a and b)

Mathematics

1 answer:

ZanzabumX [31]1 year ago

5 0

a. θ = 36. 9°

b. θ = 114. 2°

<h3>How to determine the value of theta</h3>

a. We use the cosine identity

cos θ = adjacent/hypotenuse

Adjacent = 4cm

Hypotenuse = 5cm

cos θ = 4/ 5

cos θ = 0. 8

Now, we have the inverse of the cosine value

θ = cos^-1 (0. 8)

θ = 36. 9°

b. We use the tangent identity

tan a = opposite / adjacent

tan a = 3. 8/1. 7

tan a = 2. 23

a = tan^-1 ( 2. 23)

a = 65. 8

We have;

a + θ = 180 °; angles on a straight line

θ = 180 - 65. 9

θ = 114. 2°

Learn more about trigonometric identities here:

brainly.com/question/7331447

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Answer:

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Step-by-step explanation:

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✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

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✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

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3 years ago

Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th

DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that $A \cap B$ = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

$A + (A \cap B) = 0.40$

$A + 0.17 = 0.40$

$A = 0.23$

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

$B + (A \cap B) = 0.35$

$B + 0.17 = 0.35$

$B = 0.18$

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

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Answer:

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3 years ago

Find the value of Theta in these diagrams (a and b)​

Find the value of Theta in these diagrams (a and b)