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Mekhanik [1.2K]
3 years ago
13

What is the discriminant of the quadratic equation, 4x^2-8x-5=0​

Mathematics
2 answers:
uysha [10]3 years ago
7 0

Answer:

Step-by-step explanation:

4x^2-8x-5=0

The discriminant is the number under the √. In this case it's 144

Gennadij [26K]3 years ago
4 0

Answer:

\Delta=144

Step-by-step explanation:

For a quadratic in standard form, the discriminant is given by:

\Delta=b^2-4ac

We have the equation:

4x^2-8x-5=0

Hence, our a=4; b=-8; and c=-5.

Substituting into our formula, we acquire:

\Delta=(-8)^2-4(4)(-5)

Evaluate:

\Delta=64+80

Add:

\Delta=144

Therefore, our discriminant is 144.

Notes:

Since our discriminant is a positive value, this tells us that our quadratic has two real roots.

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