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2 years ago

A confidence interval is a range of values used to estimate the true value of a?

1 answer:

5 0

A confidence interval is a range of plausible values for the population parameter with a level of confidence attached.

In frequency statistics, a confidence interval is the range of estimated values for an unknown parameter. Confidence intervals are computed at the specified confidence level. A 95% confidence level is the most common, but other levels such as 90% and 99% are sometimes used.

Confidence intervals are defined as the range of values that you would expect to observe in a sample and find a value that accurately reflects the population.

Confidence intervals are a way of expressing how "good" an estimate is. The larger the 90% confidence interval for a particular estimate, the more cautious it should be used. Confidence intervals are an important reminder of the limits of an estimate.

Learn more about confidence interval here: brainly.com/question/17097944

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Given the graph of a function f. Identify the function by name. Then Graph, state domain & range in set notation:A) f(x) +2B

WARRIOR [948]

The function in the graph has the name of square function.

The domain of a function is all values of x the function can have. The domain of this function is all real numbers:

$\mleft\lbrace x\in\R\mright\rbrace$

The range of a function is all values of y the function can have. The range of this function is all positive numbers, including zero:

$\mleft\lbrace y\in\R\mright|y\ge0\}$

In order to graph f(x) + 2, we just need to translate the graph 2 units up. To find the new points, we need to increase all y-coordinates by 2:

(-2, 6), (-1, 3), (0, 2), (1, 3), (2, 6)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ 2}

Then, in order to graph f(x) - 2, we just need to translate the graph 2 units down. To find the new points, we need to decrease all y-coordinates by 2:

(-2, 2), (-1, -1), (0, -2), (1, -1), (2, 2)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ -2}

4 0

1 year ago

Two sides of an obtuse triangle measure 9 inches and 14 inches. The length of longest side is unknown. What is the smallest poss

julia-pushkina [17]

Answer:

17 inches

Step-by-step explanation:

An obtuse triangle is the triangle in which one of the side is the longest. It contains an obtuse angle and the longest side is the side that is opposite to the vertex of the obtuse angle.

Let the three sides of the obtuse triangle be a, b and c respectively with c as the longest side. Let a = 9 inches and b = 14 inches.

Now we know that for an obtuse triangle,

$c^2 > a^2 +b^2$

$c^2 > (9)^2 +(14)^2$

$c^2 > 81 +196$

$c^2 > 277$

c > 16.64

Therefore the smallest possible whole number is 17 inches.

4 0

3 years ago

Read 2 more answers

Express p in terms of q if

Irina-Kira [14]

$p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)$

$q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}$

8 0

3 years ago

the boundary of a rectangular farm field in ireland has a straight rock wall along one side and fences along its other three sid

Inessa [10]

Answer:

781250 $ft^{2}$

Step-by-step explanation:

Let y is the length of the farm field

Let x is the width of the farm field

Given that, no fencing is necessary along the rock wall, so we can find the perimeter of the farm is:

2x + y = 2500 feet

<=> y = 2500 -2x

The are of the farm has the following formula:

A = x*y

<=> A = x(2500 - 2x)

<=> A = 2500x -2 $x^{2}$

To have the maximum area of field in square feet, we need to use differentials to estimate:

$\frac{dA}{dx}$ = 2500 - 4x

Set $\frac{dA}{dx}$ = 0, we have:

2500 - 4x = 0

<=> x = 625 feet.

=> y = 2500 - 2*625 = 1250 feet

So the maximum area of field is:

A = x*y = 625*1250 = 781250 $ft^{2}$

7 0

4 years ago

I need heeeeeeeeeeelllllllllllllppppppppppp!?!

kati45 [8]

Answer:

I cant give you an answer but hints:

First you gotta know the angles of the triangle

then how many are there

then those lines in the middle is dividing lines so

right angles are 90 degrees

I would go for B then.

if not I'm sorry

3 0

3 years ago

Read 2 more answers