Question

Select the correct answer from each drop-down menu. franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6. the probability that the sum of the numbers rolled is either even or a multiple of 5 is . the probability that the sum of the numbers rolled is either a multiple of 3 or 4 is .

Answer 1

The probability that the sum of the numbers rolled is either even or a multiple of 5 is 22/36 or 11/18.

The probability that the sum of the numbers rolled is either a multiple of 3 or a multiple of 4 is 20/36 or 5/9.

The outcomes of rolling two dices together are:

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6).

The sum of the outcomes on the dice are:

2, 3, 4, 5, 6, 7,

3, 4, 5, 6, 7, 8,

4, 5, 6, 7, 8, 9,

5, 6, 7, 8, 9, 10,

6, 7, 8, 9, 10, 11,

7, 8, 9, 10, 11, 12.

Now, we are asked for the probability that the sum of the numbers rolled is either even or a multiple of 5.

Favorable outcomes = 2, 4, 5, 6, 4, 5, 6, 8, 4, 5, 6, 8, 5, 6, 8, 10, 6, 8, 10, 8, 10, 12.

Thus, the number of favorable outcomes = 22.

The total number of outcomes = 36.

Thus, the probability that the sum of the numbers rolled is either even or a multiple of 5 is 22/36 or 11/18.

Now, we are asked for the probability that the sum of the numbers rolled is either a multiple of 3 or a multiple of 4.

Favorable outcomes = 3, 4, 6, 3, 4, 6, 8, 4, 6, 8, 9, 6, 8, 9, 6, 8, 9, 8, 9, 12.

Thus, the number of favorable outcomes = 20.

The total number of outcomes = 36.

Thus, the probability that the sum of the numbers rolled is either a multiple of 3 or a multiple of 4 is 20/36 or 5/9.

Learn more about the probability at

brainly.com/question/23955312

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