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laiz [17]
1 year ago
9

A COUPLE PLAN TO HAVE SIX CHILDREN. HOW MANY POSSIBLE OUTCOMES ARE IN THE SAMPLE SPACE?

Mathematics
1 answer:
Zinaida [17]1 year ago
6 0

Since there are 6 elements in the given set, hence the possible outcome in the sample space is 6

<h3>What is probability?</h3>

Probability is the likelihood or chance that an event will occur. Mathematically, the formula for calculating probability is expressed as:

Probability = expected outcome/Total outcome

Sample space is the total number of element in a given set of probability. The subsets if this sets are called event

Let the six children the couple plan to have ne 1, 2, 3, 4, 5,6 such that the sample space will be:

S = {1, 2, 3, 4, 5, 6}

Since there are 6 elements in the given set, hence the possible outcome in the sample space is 6

Learn more on sample space here: brainly.com/question/10558496

#SPJ1

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I will give Brainliest!!
sergey [27]

The value of y in the triangle is 6°.

<h3>How to calculate the value of y in the triangle?</h3>

Firstly, it's important to note that a triangle has the total angles of 180°.

Based on the information, the triangle has interior angle measures of 11y, 10y + 10°, and 10y - 16º.

The value of y in the triangle will be illustrated thus:

11y + 10y + 10 + 10y - 16 = 180

31y - 6 = 180

31y = 180 + 6.

31y = 186

Divide.

y = 186 / 31

y = 6

The value of y is 6.

Learn more about triangles on:

brainly.com/question/17335144

#SPJ1

5 0
2 years ago
Engineers want to design passenger seats in commercial aircraft so that they are wide enough to fit 95 percent of adult men. Ass
zimovet [89]

Answer:

z=1.64

And if we solve for a we got

a=14.4 +1.64*1.1=16.204

The 95th percentile of the hip breadth of adult men is 16.2 inches.

Step-by-step explanation:

Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:

X \sim N(14.4,1.1)  

Where \mu=14.4 and \sigma=1.1

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.05   (a)

P(X   (b)

We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64

Using this value we can set up the following equation:

P(X  

P(z

And we have:

z=1.64

And if we solve for a we got

a=14.4 +1.64*1.1=16.204

The 95th percentile of the hip breadth of adult men is 16.2 inches.

8 0
3 years ago
Can someone please help !!!
Vera_Pavlovna [14]

Answer:

A = 6.3033315211545 in2 or 6.3

Step-by-step explanation:

7 0
3 years ago
Which of the following values are solutions to the inequality -10_&gt;6x-4
qaws [65]

Answer:

3rd option

Step-by-step explanation:

- 10 ≥ 6x - 4 ( add 4 to both sides )

- 6 ≥ 6x , then

6x ≤ - 6 ( divide both sides by 6 )

x ≤ - 1

Thus x = - 1 is a solution to the inequality

6 0
3 years ago
Identify the function that best models the data.
In-s [12.5K]
The answer you are  looking for is A, I'm a little rusts at these but that should your answer have a good day!
7 0
3 years ago
Read 2 more answers
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