The perimeter = 4 * length of a semicircle of radius 5 == 4* pi * 5 = 20 pi cm
The area of one of the clear parts = 1/2 area of square - area semicircle
= 1/2 * 10^2 - 1/2 pi *5^2 = 50 - 12.5pi
So area of shaded parts = area of square - 4 (50 - 12.5pi)
= 100 - 200 + 100pi = (100pi - 100) cm^2
Answer:
300
Step-by-step explanation:
5fg
5(6)(10)=300
Value of x is 9 and measure of each side is 35 units.
<u>SOLUTION:
</u>
Given, Triangle QRS is an equilateral triangle.
QR is seventeen more than twice x, 
RS is 19 less than six times x, 
And QS is one less four times x, 
We have to find x and measure of each side.
Now, we know that, sides of equilateral triangle are equal,
Then 
So, value of x is 9.
Hence, value of x is 9 and measure of each side is 35.
Answer:
Interquartile Range
The interquartile range of an observation variable is the difference of its upper and lower quartiles. It is a measure of how far apart the middle portion of data spreads in value.
Interquartile Range = U pper Quartile − Lower Quartile
Problem
Find the interquartile range of eruption duration in the data set faithful.
Solution
We apply the IQR function to compute the interquartile range of eruptions.
> duration = faithful$eruptions # the eruption durations
> IQR(duration) # apply the IQR function
[1] 2.2915
Answer
The interquartile range of eruption duration is 2.2915 minutes.
Exercise
Find the interquartile range of eruption waiting periods in faithful.
Step-by-step explanation:
