All categories

2 years ago

3 x +14 (3x-4) +3 x ( 6) +3 (х+2 )=4

Mathematics

1 answer:

masha68 [24]2 years ago

8 0

The value of 'x' from the expression is 9/ 11

<h3>How to simplify the expression</h3>

Given the expression;

3 x +14 (3x-4) +3 x ( 6) +3 (х+2 )=4

First, we expand the bracket

3x + 42x - 56 + 18x + 3x + 6 = 4

collect like terms

3x + 42x + 18x + 3x - 56 + 6 = 4

Add up like terms

66x - 50 = 4

66x = 4 + 50

66x = 54

Make 'x' the subject of formula

x = 54/ 66

x = 9/ 11

Thus, the value of 'x' from the expression is 9/ 11

Learn more about algebraic expressions here:

brainly.com/question/4344214

#SPJ1

You might be interested in

An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e

uranmaximum [27]

Answer:

The answers are for option (a) 0.2070 (b)0.3798 (c) 0.3938

Step-by-step explanation:

Given:

Here Section 1 students = 20

Section 2 students = 30

Here there are 15 graded exam papers.

(a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070

(b) Here if x is the number of students copies of section 2 out of 15 exam papers.

here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15

Then,

Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798

(c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1)

so,

Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938

Note : Here the given distribution is Hyper-geometric distribution

where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.

7 0

3 years ago

phyllis invested 66000 dollars, a portion earning simple interest rate of 5% per year and the rest earning a rate of 7% per year

Lelechka [254]

Answer:

Physliis invested 32000 dollar at 5% interest rate and 34000 dollar at 7% interest rate.

Solution:

Let Phyllis invest ‘x’ dollar at 5% per year and (66000-x) dollar at 7% per year.

We know,

$\text { Simple interest }=\frac{\text {Principal} \times r a t e \times T i m e}{100}$

In the question it is given that Simple interest earned from both the investments at the end of the year is $3980.

Using the given below equation, we will try to find out the investments at each rate.

$\begin{array}{l}{\frac{x \times 5 \times 1}{100}+\frac{(66000-x) \times 7 \times 1}{100}=3980} \\\\ {\frac{5 x}{100}+\frac{462000-7 x}{100}=3980} \\\\ {\frac{5 x+462000-7 x}{100}=3980} \\\\ {-2 \mathrm{x}+462000=3980 \times 100} \\\\ {-2 \mathrm{x}=398000-462000} \\\\ {-2 \mathrm{x}=-64000} \\\\ {\mathrm{x}=\frac{-64000}{-2}}\end{array}$