Answer:
0.25ab
Step-by-step explanation:
Data provided in the question:
f(x) = xa(1−x)b, 0≤x≤1
or
f(x) = ab(x−x²)
for point of maxima and minima put f'(x) = 0
Thus,
f'(x) = ab(1 - 2x) = 0
or
1 - 2x = 0
or
x = 
= 0.5
Now,
to check the condition of maxima or minima
f''(x) = ab(0 - 2) = -2ab
since,
f''(x) < 0
therefore,
x = 0.5 is point of maxima
and the maximum value at x = 0.5 of the function is
f(0.5) = ab(0.5 - 0.5²)
= ab(0.25)
= 0.25ab
Graphing what? there isn’t a picture
Answer:
34'2" I think
Step-by-step explanation:
You just add them together and that was for the first part
Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯
Giving your answer as an interval, find all values of x for which the series converges.
Now assuming that x is in your interval above, find a simple formula for S(x).
Answer:
<h2>
43.4° and 46.6°</h2>
Step-by-step explanation:
x - measure of angle
x + 3.2° - measure of its complementary angle
Complementary angles adds to 90°
x + x + 3.2° = 90°
2x = 90° - 3.2°
2x = 86.8°
x = 86.8°÷2
x = 43.4°
x+3.2° = 43.4° + 3.2° = 46.6°
