Find the Sample size for 99% confidence level with a margin of error of 4% and p unknown.
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Answer:
<h2>Therefore the length of a side of a cube isStep-by-step explanation:
The volume of a cube is expressed as L³ where L is the length of each side of the cube.
Given volume of a cube = 64in³
On substituting;
64 = L³
Taking the cube root of both sides to determine L we have;
Therefore the length of a side of a cube is
Pretend these are coordinates that you can use to find the slope of the line.
(10, 40) and (15, 60). Fit these into the slope formula to find the slope of the line you are looking for:
and the slope is 4. Now use one of the points and the slope of 4 to solve for b, the y-intercept:
40 = 4(10) + b so b = 0. The equation of the line then is y = 4x + 0 or just
y = 4x
(10, 40) and (15, 60). Fit these into the slope formula to find the slope of the line you are looking for:
40 = 4(10) + b so b = 0. The equation of the line then is y = 4x + 0 or just
y = 4x
The question is incomplete. The complete question is :
The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.
b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.
a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)
b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)
Solution :
Given :
The volume of the right circular cone with a radius r and height h is
a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96
So, r = 5.9 and dr = 6.8 - 5.9 = 0.9
h = 4 and dh = 3.96 - 4 = -0.04
Now,
Therefore, the approximate change in volume is dV = 43.03 cubic units.
b). The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92
So, r = 6.47 and dr = 6.45 - 6.47 = -0.02
h = 10 and dh = 9.92 - 10 = -0.08
Now,
Hence, the approximate change in volume is dV = -6.22 cubic units