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1 year ago

If X = 2 centimeters, Y = 5 centimeters, and Z = 5 centimeters, what is the area of the object?

Mathematics

1 answer:

Elena L [17]1 year ago

6 0

Answer: $35 cm^2$

Step-by-step explanation:

Area of trapezium =

2X = 2 + 2 = 4 cm

2Z = 5 + 5 = 10 cm

Y = 5 cm

$\dfrac{ \left( 4+10 \right) }{ 2 } \times 5$

|--------> 35 $cm^2$

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6 children and 2 adults are going to the circus. Children tickets are on sale,half price of adult tickets totaling $54. How much

Anon25 [30]

Answer:

Price of 1 adult ticket is $10.8 and Price of 1 children ticket is $5.4.

Step-by-step explanation:

Given:

Number of adults = 2

Number of Children = 6

Total Amount of tickets sold = $54.

We need to find the price of one children's ticket and one adult ticket.

Solution:

Let the Cost of 1 adult ticket be 'x'.

Now Given:

Children tickets are on sale,half price of adult tickets.

Cost of 1 Children ticket = $\frac{1}{2}x$

Total Amount is equal to Number of adults multiplied by Cost of adult ticket plus Number of Children multiplied by Cost of Children ticket.

Framing in equation for we get;

$2x+\frac{1}{2}x\times 6=54\\\\2x+3x=54\\\\5x=54\\\\x=\frac{54}{5} = \$10.8$

Cost of 1 adult ticket = $10.8

Cost of 1 children ticket = $\frac{x}{2}=\frac{10.8}{2} = \$5.4$

Hence Price of 1 adult ticket is $10.8 and Price of 1 children ticket is $5.4.

7 0

4 years ago

. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?

UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

As we know:

$Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \ of\ I-pad}$

$5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2$

a) Thus, the total width of the I-Pads are 61.2 inches.

$Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \ of\ Kindles}$

$4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4$