The area of the rectangle ACEG is the amount of space on it, and the area of square HJFG is 9 square units
<h3>How to determine the area of the figures?</h3>
The area of a rectangle is:
Area = Length * Width
The area of a square is:
Area = Length * Length
From the question, the given parameters are:
AB =AH = x ;
BC=5;
HG=3
This means that the area of square HJFG is:
Area = HG * HG
Area = 3 * 3
Area = 9
<em>Note that the other areas cannot be calculated because the question is incomplete</em>
<em />
Read more about areas at:
brainly.com/question/17335144
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What is the median of the data?<br>30,29,16,11,16,20,21,12,13,15,15,23,30
tia_tia [17]
Answer:
16
Step-by-step explanation:
ascending order:11,12,13,15,15,16,16,20,21,23,29,30,30
number of terms =13
median=[(n+1)/2] th term
=[(13+1)/2] th term
=[14/2] th tem
=7th term
=16
![\dfrac{d}{dx}(\dfrac{\sin(3x)}{x})](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%28%5Cdfrac%7B%5Csin%283x%29%7D%7Bx%7D%29)
First we must apply the Quotient rule that states,
![(\dfrac{f}{g})'=\dfrac{f'g-g'f}{g^2}](https://tex.z-dn.net/?f=%28%5Cdfrac%7Bf%7D%7Bg%7D%29%27%3D%5Cdfrac%7Bf%27g-g%27f%7D%7Bg%5E2%7D)
This means that our derivative becomes,
![\dfrac{\dfrac{d}{dx}(\sin(3x))x-\dfrac{d}{dx}(x)\sin(3x)}{x^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cdfrac%7Bd%7D%7Bdx%7D%28%5Csin%283x%29%29x-%5Cdfrac%7Bd%7D%7Bdx%7D%28x%29%5Csin%283x%29%7D%7Bx%5E2%7D)
Now we need to calculate
and ![\dfrac{d}{dx}(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%28x%29)
![\dfrac{d}{dx}(\sin(3x))=\cos(3x)\cdot3](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%28%5Csin%283x%29%29%3D%5Ccos%283x%29%5Ccdot3)
![\dfrac{d}{dx}(x)=1](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%28x%29%3D1)
From here the new equation looks like,
![\dfrac{3x\cos(3x)-\sin(3x)}{x^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B3x%5Ccos%283x%29-%5Csin%283x%29%7D%7Bx%5E2%7D)
And that is the final result.
Hope this helps.
r3t40
Answer:
4fv5
Step-by-step explanation:
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