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3 years ago

What is the distance between-4 1/2 and -1 on number line

Mathematics

1 answer:

sergejj [24]3 years ago

6 0

Answer:

The difference between - 4 1/2 and -1 is -3 1/2

—4 1/2 --(—1)

— 4 1/2 + 1

— 3 1/2

Step-by-step explanation:

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Are 30:12 and 40:16 equivelant if noy tell why

mihalych1998 [28]

They are equivalent

30:12 => 5:2
40:16 => 5:2

hope this helsp

4 0

3 years ago

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6

USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

The coordinates are given as:

$\mathbf{(x,y) = (-60,0)\ (60,0)}$

The center of the hyperbola is

$\mathbf{(h,k) = (0,0)}$

The distance from the center to the focal points is given as:

$\mathbf{c = 60}$

Square both sides

$\mathbf{c^2 = 3600}$

The distance from the receiver to the transmitters is given as:

$\mathbf{2a = 100}$

Divide both sides by 2

$\mathbf{a = 50}$

Square both sides

$\mathbf{a^2 = 2500}$

We have:

$\mathbf{b^2 = c^2 - a^2}$

This gives

$\mathbf{b^2 = 3600 - 2500}$

$\mathbf{b^2 = 1100}$

The equation of an hyperbola is:

$\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}$

So, we have:

$\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}$

$\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Hence, the equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Read more about hyperbolas at:

brainly.com/question/15697124

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3 years ago

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Which of the following numbers is a perfect number (Hint: try to use the

Nitella [24]

C. 496 is the perfect number

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4 years ago

What is the slope of the linear function above? Write any fractions as improper fractions, using a '/'. (PLEASE HELP ME)

aliina [53]

-3/2
Down 3
Right 2
As an improper fraction it would be -1 1/2

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2 years ago

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Assume that the weights of quarters are normally distributed with a mean of 5.67 g and a standard deviation of 0.07 g. If a vend

Black_prince [1.1K]

Answer:

0.98046

Step-by-step explanation:

Given:

μ = 5.67

σ = 0.07

Here we are required to find

P(5.48 <X<5.82) and between 5.48 and 5.82 we each z-score given by

So 5.48 we have z = -2.714 and 5.82 we have z = 2.143

Therefore we have the area of interest on the normal distribution chart given by :

P( -2,714 < z < 2.143)

= 1 - P(Z<-2.714) + P(Z > 2.143)

= 1 - P(Z<-2.714) + (1 - P(Z < 2.143))

= 1 - 0.00336 + 1 - 0.98382

= 1 - 0.01954 = 0.98046

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3 years ago

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