1) 300miles X $0.20 = $60
2) $50 + $60 = $110
They spent $110 for the car.
Answer:
Step-by-step explanation:
tan P =
=
tan Q =
Split up the interval [2, 5] into

equally spaced subintervals, then consider the value of

at the right endpoint of each subinterval.
The length of the interval is

, so the length of each subinterval would be

. This means the first rectangle's height would be taken to be

when

, so that the height is

, and its base would have length

. So the area under

over the first subinterval is

.
Continuing in this fashion, the area under

over the

th subinterval is approximated by

, and so the Riemann approximation to the definite integral is

and its value is given exactly by taking

. So the answer is D (and the value of the integral is exactly 39).
Answer:
The speed is equal to 
Step-by-step explanation:
we know that
The speed is equal to divide the distance by the time
Let
x------> the distance in miles
y-----> the time in hours
s----> the speed in mph
so

In this problem we have


substitute
