The voice onset time (vot) for the sound /da/ is 17 ms, and the vot for the sound /ta/ is 91 msec. When a computer produces a so
1 answer:
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Answer:
0
Step-by-step explanation:
This equation is in "vertex form," meaning that you can identify the vertex and other features of the graph from the equation.
y = a(x -h)² +k . . . . . the vertex is (h, k); the vertical scale factor is "a"
Comparing to your equation, you see ...
a = -1/2, h = 3, k = -1
The vertex is (h, k) = (3, -1). The vertical scale factor is negative.
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This tells you the graph opens downward (the scale factor is negative), and the vertex (maximum point) is below the x-axis. (It has a negative y-coordinate.)
Because it start below the x-axis and goes down from there, the graph does not intersect the x-axis. There are zero (0) x-intercepts.
Answer:
a)
b)
c) On this case it's not the same since the proportion estimated for 1983 it's different from the proportion estimated for 2008. So since the margin of error depends of the margin of error change for part a and b.
Step-by-step explanation:
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The population proportion have the following distribution
The margin of error for the proportion interval is given by this formula:
(a)
If solve n from equation (a) we got:
(b)
Part a
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by and
. And the critical value would be given by:
If we replace the values into equation (a) for 1983 we got:
Part b
Since is the same confidence level the z value it's the same.
If we replace the values into equation (a) for 2008 we got:
Is the margin of error the same in parts (a) and (b)? Why or why not?
On this case it's not the same since the proportion estimated for 1983 it's different from the proportion estimated for 2008. So since the margin of error depends of the margin of error change for part a and b.