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sesenic [268]
3 years ago
11

What is the slope of a line with endpoints (2,3) and (6,8)?

Mathematics
2 answers:
horsena [70]3 years ago
5 0

Answer: \dfrac{5}{4}

Step-by-step explanation:

The slope of a line passing through (a,b) and (c,d) is given by :-

m=\dfrac{d-b}{c-a}

The given points : (2,3) and (6,8)

Then, the  slope of the line passing through (2,3) and (6,8) is given by :-

m=\dfrac{8-3}{6-2}=\dfrac{5}{4}

Hence, the  slope of a line with endpoints (2,3) and (6,8) = \dfrac{5}{4}

Yuki888 [10]3 years ago
4 0

We don't need to graph the line. All we have to do is use our slope formula.

Answer is provided in the image attached.

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3 years ago
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soldi70 [24.7K]

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Step-by-step explanation:

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3 years ago
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Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
yuradex [85]

Answer:

0 < t < 5 is the required interval for the differential equation (t - 5)y' + (ln t)y = 6t to have a solution.

Step-by-step explanation:

Given the differential equation

(t - 5)y' + (ln t)y = 6t

and the condition y(1) = 6

We can rewrite the differential equation by dividing it by (t - 5) as

y' + [(ln t)/(t - 5)]y = 6t/(t - 5)

(ln t)/(t - 5) is continuous on the interval (0, 5) and (5, +infinity).

6t/(t - 5) is continuous on (-infinity, 5) and (5, +infinity)

We see that for these expressions, we have continuity at the intervals (0, 5) and (5, +infinity).

But the initial condition is y = 6, when t = 1.

The solution to differential equation is certain to exist at (0, 5)

Which implies that

0 < t < 5

is the required interval.

3 0
4 years ago
Help me on this please
kolbaska11 [484]
The answer : C
Yea its C
5 0
2 years ago
The principal at Riverside High School would like to estimate the mean length of time each day that it takes all the buses to ar
Lilit [14]

Answer:

C) 11

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    

And on this case we have that ME =7 and we are interested in order to find the value of n, if we solve n from the last equation we got:

n=(\frac{z_{\alpha/2} s}{ME})^2  

And replacing the values that we got we have:

n=(\frac{1.64(14)}{7})^2 =10.758 \approx 11

C) 11

8 0
3 years ago
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