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Phoenix [80]
1 year ago
5

Consider the given statement.

Mathematics
1 answer:
Novosadov [1.4K]1 year ago
7 0

Answer:

  1. Negation
  2. Statement
  3. Equivalent
  4. Neither

Step-by-step explanation:

<u>If it is not Monday, then there are students in the gym.</u>

<em>Negation:</em> It is not Monday and there are not students in the gym.

<em>Statement:</em> It is Monday or there are students in the gym.

<em>Equivalent:</em> If there are not students in the gym, then it is Monday.

<em>Neither:</em> There are not students in the gym or it is not Monday.

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Can someone help my cousin? hes in 5th grade and im not sure if im right with this question. :)
agasfer [191]

Answer: 2.25 = 18.90

Step-by-step explanation: Hope This Helps

7 0
3 years ago
Given that 8 bolts and 6 nuts weigh 138grams and 3 bolts and 5 nuts weigh 71 grams. Find the weight of;(a)one bolt and one nut (
Viktor [21]

Answer:

(a) Weight of a bolt = 12 grms and weight of a nut is 7 gms. Weight of one bolt and one nut = 12 + 7 = 19 gms

(b) 69 gms

(c) 209 gms

Step-by-step explanation:

This problem relates to solution of 2 unknowns using simultaneous equations.

Let B be the weight of a single bolt and N be the weight of a single nut

Since 8 bolts and 6 nuts weigh 138 grams we get one of the equations as

8B + 6N = 138    (1)

The second equation in the unknowns is

3B + 5N = 71  (2)

To solve, we eliminate one of the unknowns by making its coefficients the same and subtracting one from the other

Multiplying (1) by 5 ===>   40B + 30N = 690   (3)

Multiplying (2) by 6 ===>  18B + 30N = 426    (4)

(3) - (4) eliminates the N variables and yields

22B = 264   ==> B = 264/22 ==> B = 12

So the weight of a single bolt is 12 grams

We can find the weight of a single nut by substituting this value of B into any of the equations (1), (2), (3) or (4) and solving for N. Let's use equation (2)

3(12) + 5N = 71 ==>  36 + 5N = 71 ==> 5N = 71-36 = 35 ==>  N= 7

So the weight of a single nut is 7 grams

Weight of one bolt and one nut is the sum of the above individual weights = 12 + 7 = 19 gms

To solve (b) and (c) we could set up two other equations and plug in values for B and N

(b) 4B + 3N = 4.12 + 3.7 = 69
However, an alternate way is to perceive that 4B + 3N is exactly half of 8B + 6N so the value of that must be 138/2 = 69

(c) If we add both equations (1) and (2), we get

11B + 11N = 138 + 71 = 209 which is the equation for the total weight of 11 bolts and 11 nuts

5 0
1 year ago
Solve 2x-8=-2-8. How do I do this
faust18 [17]
Is that negative 2 minus 8? if so put that into the calculator and add 8 to both sides and divide by 2 after that. simple algebra
5 0
3 years ago
Read 2 more answers
HELP!! To find the quotient of two fractions, you first need to rewrite the division problem as an equivalent multiplication pro
sergey [27]
1. 5/6

2. 2/3 x 5/6

3. 2/3 x 5/6 = 10/18
Multiply the numerators— 2 x 5 = 10
Multiply the denominators—3x 6= 18

4. 10/18 = 5/9
Find the greatest common factor of 10 and 18 which is 2.
Divide the numerator by 2– 10/2 = 5
Divide the denominator by 2– 18/2 = 9

I hope this helps!
6 0
2 years ago
HELP ME A.S.A.P. PLZZZZ
Ronch [10]

Answer:

A = 66.5 in²

Step-by-step explanation:

There are a few different equations to find the area of a rhombus.  If you are given the measurements of the two diagonals, you can use the following formula:  

Area (A) = \frac{d_{1}d_{2} }{2}

Using this formula, you can multiply the measures of the diagonals and then divide by 2:

area = \frac{(9.5)(14)}{2} =\frac{133}{2}=66.5in^{2}

7 0
3 years ago
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