Find the area of this, FIRST CORRECT GETS BRANLIEST

HELPPP FIRST PERSON TO ANSWER GETS BRAINLIEST

allsm [11]

Answer:

it's C

Step-by-step explanation:

5 0

3 years ago

Natalie is buying potatoes at the grocery store. If she buys 6 potatoes that each have a mass of 375 grams, what is the total ma

larisa [96]

375x6 =2250 g

g to kilogram is divided by 1000

2250/1000 = 2.25 kg

D

4 0

4 years ago

In a blueprint, each square has a side length of 1/4 inch. Ceramic tile costs $5 per square foot. How much would it cost to tile

Bingel [31]

b.

Bedroom area

Lenght = 5 squares

= 5 × 1/4 inchi

= 5/4 inchi

Width = 4 squares

= 4 × 1/4 inchi

= 1 inchi

Large area = 5/4 × 1 inchi

= 5/4 inchi

Living room

Lenght = 7 squares

= 7 × 1/4 inchi

= 7/4 inchi

Width = 4 squares

= 4 × 1/4 inchi

= 1 inchi

Large area = 7/4 × 1 inchi

= 7/4 inchi

Total Area

Bedroom area + Living room area

= 5/4 + 7/4

= (5+7)/4 inchi

= 12/4 inchi

= 3 inchi

1 square yard = 1296 square inches

so 1 square inches = 1/1296 square yard

3 inchi = 3×1/1296

= 3/1296

= 1/432

Cost = 1/432 × $18

= $1/24

It would cost $1/24 to carpet the bedroom and living room.

6 0

2 years ago

Show your work! I really need the answer with the work!

anzhelika [568]

The surface area is 216 cm sq.

Square base formula: length * width

One square base is 70 cm sq (7*10), another is 56 cm sq (7*8), and the final base is 42 cm sq (7*6).

The height of both triangular faces is 4.8 cm

The two triangular faces are 24 cm sq each, 48 cm sq when added together.

Add all 5 numbers up to get 216.

3 0

3 years ago

In October 1945, the Gallup organization asked 1,487 randomly sampled Americans, "Do you think we can develop a way to protect o

GalinKa [24]

Answer:

Yes. There is enough evidence to support the claim that the proportion of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945 is significantly greater than 0.5.

Step-by-step explanation:

The question is incomplete:

In October 1945, the Gallup organization asked 1487 randomly sampled Americans, "Do you think we can develop a way to protect ourselves from atomic bombs in case other countries tried to use them against us?" with 788 responding yes. Did a majority of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945? Use the α=0.05 level of significance.

This is a hypothesis test for a proportion.

The claim is that the proportion of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945 is significantly greater than 0.5.

Then, the null and alternative hypothesis are:

H_0: \pi=0.5\\\\H_a:\pi>0.5

The significance level is 0.05.

The sample has a size n=1487.

The sample proportion is p=0.53.

$p=X/n=788/1487=0.53$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.5*0.5}{1487}}\\\\\\ \sigma_p=\sqrt{0.000168}=0.013$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.53-0.5-0.5/1487}{0.013}=\dfrac{0.03}{0.013}=2.288$

This test is a right-tailed test, so the P-value for this test is calculated as:

$\text{P-value}=P(z>2.288)=0.011$

As the P-value (0.011) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of Americans feel the United States could develop a way to protect itself from atomic bombs in 1945 is significantly greater than 0.5.

8 0

3 years ago