Answer:
yes the internet is a type of wan
Explanation:
hope this helps
Answer:
The following are the answers given below.
a)- normal
b)- 0.36
c)- 0.03369
Explanation:
a)- The sampling distribution pattern to the proportion of the sample should be normal because test proportions nearer to the following should become more probable, as well as the test proportions further beyond the following in any way might be increasingly fewer possible.
In certain terms, that form of the distribution of the test ratio is supposed to bulge in the midst as well as a taper at the end, so that would become somewhat normal.
b)- The mean of such a sample distribution should become identical for the actual 36% of the following users.
Consequently, p=0.36
c)- Given:
p=0.36
So, let the standard deviation should be SD.
Hey user
l think it is
<span>the polygon viewing on the default screen</span>
Answer:
harris_poll_ranking = int(input("Enter team's Harris Poll ranking [1 - 2,850]: "))
coaches_poll_ranking = int(input("Enter team's Coaches Poll ranking [1 - 1,475]: "))
computer_ranking = float(input("Enter team's computer ranking [0 - 1]: "))
harris_poll_score = harris_poll_ranking / 2850
coaches_poll_score = coaches_poll_ranking / 1475
bcs_score = harris_poll_score / 3 + coaches_poll_score / 3 + computer_ranking / 3
print(bcs_score)
Explanation:
*The code is in Python.
Ask the user to enter the harris_poll_ranking as int, coaches_poll_ranking as int and computer_ranking as float
Calculate the harris_poll_score, divide the harris_poll_ranking by 2850
Calculate the coaches_poll_score, divide the coaches_poll_ranking by 1475
Calculate the bcs_score, harris_poll_score, coaches_poll_score and computer_ranking by 3 and sum them
Print the bcs_score