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BabaBlast [244]
1 year ago
8

What is the value of x in the geometric sequence x, 3, -1/3.......?

Mathematics
1 answer:
andrey2020 [161]1 year ago
8 0

The value of x in the geometric sequence is -3.

Option (A) is correct.

To find the value of x.

<h3>What is geometric progression?</h3>

A progression of numbers with a constant ratio between each number and the one before .A geometric progression is a sequence in which any element after the first is obtained by multiplying the preceding element by a constant called the common ratio which is denoted by r. For example, the sequence 1, 2, 4, 8, 16, 32… is a geometric sequence with a common ratio of r = 2.

Given that:

The geometric sequence are x, 3, -1/3.......

Let x  = a be  the first term

3 = a*r = x *r , is second term

r is the common ratio,

r =3/x

- 1/3 = ar^2 = x r^2

substitute r, and solve for x:

-1/3 = x*3*3/x*x

cancel out the x term from numerator and denominator we have,

-1/3=9/x

By cross multiplication,

x=-9/3

By simplifies

x=-3

first term is x = -3

So, the value of x in the geometric sequence is -3.

Learn more about geometric progression here:

brainly.com/question/28189673

#SPJ1

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An easier way to do this would be to recognize that a^2, b^2, and c^2 are all equal to the area of their respective squares, since the area of a square is equal to its side squared, and the Pythagorean theorem is also squaring the sides.

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