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Over [174]
1 year ago
15

Serum cholesterol levels of 100 hypertensive patients were recorded. Mean cholesterol level was 190 mg/d1. The data was symmetri

cally distributed around the mean. Roughly 68% of the patients had serum cholesterol level between 175 mg/dl and 205 mg/dl. a. Calculate the standard error b. What will be the range of 95% confidence interval?
SAT
1 answer:
xxTIMURxx [149]1 year ago
6 0

The standard error is 1.5.

The range of 95% confidence interval is 160 mg/dL and 220 mg/dL

<h3>What is the standard error of the distribution?</h3>

The standard error of the distribution is calculated as follows:

  • Standard error = standard deviation/√N

where N is the number of participants = 100

From the empirical rule of a normal or symmetrical distribution;

  • 68% of the data lies within one standard deviation
  • 95% percent within two standard deviations, and
  • 99.7% within three standard deviations from the mean.

Therefore,  175 mg/dl and 205 mg/dl lie one standard deviation from the mean.

One standard deviation = 175 - 190 or 205 - 190 = ±15

Standard deviation = 15

a. Solving for the standard error using the equation above;

Standard error = 15/√100

Standard error = 1.5

b. The range of 95% confidence interval is two standard deviations away from the mean.

Range of values two standard deviations from the mean = 190 - (2*15) and 190 + (2 * 15)

Range of values two standard deviations from the mean = 160 mg/dL and 220 mg/dL

Therefore, the range of 95% confidence interval is 160 mg/dL and 220 mg/dL

In conclusion, the standard error is calculated from the standard deviation and the sample size.

Learn more about standard error at: brainly.com/question/14467769

#SPJ1

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