First, factor out a 3.
3(x² - 9)
In any quadratic ax² + bx + c, we can split the bx term up into two new terms which we want to equal the product of a and c.
In this case, we have x² + 0x - 9. (the 0x is a placeholder)
We want two numbers that add to 0 and multiply to get -9.
Obviously, these numbers are 3 and -3.
Now we have 3(x² + 3x - 3x - 9).
Let's factor.
3(x(x+3)-3(x+3))
<u>3(x-3)(x+3)</u>
There are multiple shortcuts which you could make here, FYI:
Instead of splitting the middle, if your a value is 1, you can go straight to that step (x+number)(x+other number).
Whenever you have a difference of squares, like a²-b², that factors to (a+b)(a-b).
B .35 line the numbers up by the decimals then go from top to bottom starting from each individual column.
Let's call the number of elephants x.
x+4x=35
5x=35
x=7
So there are 7 elephants. There are four times as many monkeys.
7×4=28
There are 28 monkeys.
Answer:
1357, 1359, 1579, 1573, 1375, 1379, 1957, 1953
Step-by-step explanation:
Since this number needs to be less than 2000, the first number has to be 1. You can randomly pick and choose any of the numbers after that.
Answer:
60
skip count to find lest common denominator quickly
