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tangare [24]
1 year ago
13

If you have 66 data observations in a sample, how many classes (bins) does the sturges' rule recommend for you to construct a fr

equency distribution?
Mathematics
1 answer:
Iteru [2.4K]1 year ago
8 0

According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7

Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.

Given,

n = 66

We know that,

According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

k=1+log_{2} n

Here, n is equal to 66 and by substituting the value to the equation we get:

k=1+log_{2} (66)

k = 7.0444

k ≈ 7

Learn more about Sturge's rule here: brainly.com/question/28184369

#SPJ4

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What is the solution to the following equation?
lions [1.4K]

Answer:

D. x = 7

Step-by-step explanation:

NOTE : <u><em>there should be an equal sign somewhere in the given expression.</em></u>

suppose the equation is the following:

3(x-4)-5 = x-3

………………………………………………………

3(x - 4) - 5 = x - 3

⇔ 3x - 12 - 5 = x - 3

⇔ 3x - 17 = x - 3

⇔ 3x - 17 + 17= x - 3 + 17

⇔ 3x = x + 14

⇔ 2x = 14

⇔ x = 14/2

⇔ x = 7

8 0
2 years ago
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Ivenika [448]
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5 0
3 years ago
Please help <br> Thank you
Kaylis [27]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Complete The Square:<br> (Z^2)-19z=66
Musya8 [376]
To solve the equation using complete square method we proceed:
z^2-19z=66
but
 c=(-b/2a)^2
c=(-19/2)^2
c=361/4
thus:
z^2-19z+361/4=66+361/4
factoring the LHS we get:
1/4(2z-19)^2=625/4

(2z-19)^2=625
getting the square root of both sides we get:
2z-19=+/-25
2z=+/-25+19
2z=44 or -6
z=22 or -3
Answer: z=22 or z=-3



8 0
3 years ago
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frosja888 [35]

Answer:

Step-by-step explanation:

5 0
3 years ago
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