Hey,
If you meant that
than
![= \sqrt[4]{111^{5}}](https://tex.z-dn.net/?f=%3D%20%20%5Csqrt%5B4%5D%7B111%5E%7B5%7D%7D%20%20)
but you can't find the exact number.
Hope this helps :) and don't forget to choose the brainliest please :)
Answer:
a
Step-by-step explanation:
Answer:
-1250/1 or -1250
This tells us that the car depreciated in value by $1250 every year.
Step-by-step explanation:
11,095-13,595= -2500
This is the value that the car has depreciated over 2 years (from the first year to the third year)
Since we need to find the slope we divide this value by two.
That value would be -1250
Since the value is negative, we know the car has depreciated in value. We also now know that it depreciated in value by $1250 every year
Hope this helps!
Answer:
a.
<u>Increasing:</u>
x < 0
x > 2
<u>Decreasing:</u>
0 < x < 2
b.
-1 < x < 2
x > 2
c.
x < -1
Step-by-step explanation:
a.
Function is increasing when it is going up as we go rightward
Function is decreasing when it is going down as we go rightward
We can see that as we move up (from negative infinity) until x = 0, the function is increasing. Also, as we go right from x = 2 towards positive infinity, the function is going up (increasing).
So,
<u>Increasing:</u>
x < 0
x > 2
The function is going down, or decreasing, at the in-between points of increasing, that is from 0 to 2, so that would be:
<u>Decreasing:</u>
0 < x < 2
b.
When we want where the function is greater than 0, we basically want the intervals at which the function is ABOVE the x-axis [ f(x) > 0 ].
Looking at the graph, it is
from -1 to 2 (x axis)
and 2 to positive infinity
We can write:
-1 < x < 2
x > 2
c.
Now we want when the function is less than 0, that is basically saying when the function is BELOW the x-axis.
This will be the other intervals than the ones we mentioned above in part (b).
Looking at the graph, we see that the graph is below the x-axis when it is less than -1, so we can write:
x < -1
Answer:
B
Step-by-step explanation:
4x+ (-2) =-2x+6
just took the quiz
