Answer:
There are 795 combinations.
Step-by-step explanation:
The number of ways or combinations in which we can select k element from a group of n elements is given by:
So, if Miriam want to choose 3 movies with at least two comedies, she have two options: Choose 2 comedies and 1 foreign film or choose 3 comedies.
Then, the number of combinations for every case are:
1. Choose 2 Comedies from the 10 and choose 1 foreign film from 15. This is calculated as:
2. Choose 3 Comedies from the 10. This is calculated as:
Therefore, there are 795 combinations and it is calculated as:
675 + 120 = 795
The denominator of the second fraction can be factored as (a-2)(2a-7), then it becomes doable. You cancel the (2a-7) factors, and are left with:
Do note that you have erased the fact that a≠0 and a≠7/2, so you should always mention that.
After rewriting all sets of data from smaller to greater, I found that the last series is the one that is represented by the plot box:
79,86,88,88,92,98,100,106,115,136
Why? Because The median is 95 (like the box)
because the outliers are > 115 (up to 136)
because their is no outlier on the left by the mini value of 79
Here is my theory. I did not use the Pythagorean Theorem. I used basic cross multiplication.
z = 25
t = 24
The answer is 69632 because of PEDMAS
