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prisoha [69]
3 years ago
6

Find the area and perimeter of shape ABCD with vertices A = (-1,-1), B = (2,3), C = (5,3), D = (8,-1).

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0

Answer:

Perimeter = 22

Step-by-step explanation:

To find the perimeter, we will follow the steps below:

A = (-1,-1), B = (2,3), C = (5,3), D = (8,-1).

First, we will find the distance AB

A = (-1,-1), B = (2,3)

|AB| = √(x₂-x₁)²+(y₂-y₁)²

x₁ = -1    y₁=-1     x₂=2     y₂=3

we can now proceed to insert the values into the formula

|AB| = √(x₂-x₁)²+(y₂-y₁)²

      = √(2+1)²+(3+1)²

      = √(3)²+(4)²

      = √9 + 16

      =√25

      = 5

|AB| = 5

Next, we will find the distance BC

B = (2,3), C = (5,3),

|BC| = √(x₂-x₁)²+(y₂-y₁)²

x₁ = 2    y₁=3    x₂=5     y₂=3

we can now proceed to insert the values into the formula

|BC| = √(x₂-x₁)²+(y₂-y₁)²

      = √(5-2)²+(3-3)²

      = √(3)²+(0)²

      = √9 + 0

      =√9

      = 3

|BC|=3

Next, we will find the distance CD

C = (5,3), D = (8,-1).

|CD| = √(x₂-x₁)²+(y₂-y₁)²

x₁ = 5    y₁=3    x₂=8    y₂=-1

we can now proceed to insert the values into the formula

|CD| = √(x₂-x₁)²+(y₂-y₁)²

      = √(8-5)²+(-1-3)²

      = √(3)²+(-4)²

      = √9 + 16

      =√25

      = 5

|CD|=5

Next, we will find the distance DA

D = (8,-1)      A = (-1,-1)

|DA| = √(x₂-x₁)²+(y₂-y₁)²

x₁ = 8    y₁=-1   x₂=-1    y₂=-1

we can now proceed to insert the values into the formula

|DA| = √(x₂-x₁)²+(y₂-y₁)²

      = √(-1-8)²+(-1+1)²

      = √(-9)²+(0)²

      = √81 + 0

      =√81    

      = 9

|DA|=9

PERIMETER = |AB|+|BC|+|CD|+|DA|

                     =5 + 3+5 +9

                     =22

Perimeter = 22

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