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1 year ago

Pick the correct answer Thanks so much :)

Mathematics

1 answer:

Over [174]1 year ago

5 0

The linear functions with their slopes ranked from least to greatest are given as follows:

E. I, K, J.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

In this problem, we have that:

Line I is decreasing, hence it has a negative slope.

Line K is constant, hence it has a slope of zero.

Line J is increasing, hence it has a positive slope.

Hence the linear functions with their slopes ranked from least to greatest are given as follows:

E. I, K, J.

More can be learned about linear functions at brainly.com/question/24808124

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Can someone help me pls i put rhe question as a picture i would help alot

GuDViN [60]

The answer would be D

8 0

3 years ago

Read 2 more answers

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

Find the measure of each angle indicated.<br> 7)<br> 920<br> A) 118°<br> B) 92°<br> C) 96°

Rus_ich [418]

Answer:

Its 92 degrees because they are equal. I hope this helped! plz make me brainliest

Step-by-step explanation:

5 0

3 years ago

The area of a square piece of cardboard is 81 square inches. What is the length of the cardboard

vredina [299]

9 because the square root of 81 is 9

6 0

3 years ago

Find the equation of the line through the point (2, 5) that cuts off the least area from the first quadrant. Give your answer us

Amanda [17]

The equation of the line would be

y = mx+b

where m is the slope, b is the y intercept.

<span>The line will form a triangular region in the first quadrant. Its area would be 1/2 base times height. The height is the y intercept and the base is y intercept divided by slope. Therefore,</span>

A = b^2/2m

At point (2,5)

5 = 2m+b

Substitute that in the area

A = b^2/5-b to find the least area, differentiate the area with respect to the height and equate it to 0

dA/db = 0

<span>find b and use that to find m. Then, you can have the equation of the line.</span>

4 0

3 years ago

Read 2 more answers