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marin [14]
3 years ago
9

The equation h(t)=−16t2+78t+45 gives the height of a firework, in feet, t seconds after it is launched from a platform. What is

the height of the platform? Enter your answer in the box.
Mathematics
2 answers:
Novay_Z [31]3 years ago
4 0
The height of the platform should be 45 feet. Hope this helps
algol [13]3 years ago
4 0

Answer:

45ft

should be it took the test


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Anybody know how to do lowest terms and can teach me how to get the answer to lowest terms questions?
Rzqust [24]

Answer:

Step-by-step explanation:

6/9+x=7/10

x=7/10-6/9

when adding fractions both denominators must be equal, we’ll make them 90

x=(7/10)(9/9)-(6/9)(10/10)

x=63/90-60/90

x=3/90, the greatest divisor of 3 and 90 is 3 so divide both the numerator and denominator by 3

x=(3/3)/(90/3)

x=1/30

4 0
3 years ago
A scale on a hiking map shows that 33 inches represents 1.25miles. What number of inches on the map represent 1010 actual miles?
user100 [1]

Answer:

26,664 inches  

Step-by-step explanation:

Set up a proportion to solve this...

33 inches is to 1.25 miles as 'x' inches is to 1,010 miles

33/1.25 = x/1,010        now solve for x by cross multiplying

33,330 = 1.25x

33,330/1.25 = x

26,664 = x

3 0
3 years ago
Graph x+3y<(or equal to)6, indicating the solution set with cross hatching or shading. Explain how you determine where to dra
Sergeu [11.5K]

Step 1

Given;

x+3y\leq6

Required; To graph the inequality

Step 2

Graph the function

\begin{gathered} We\text{ find the y-intercept by setting x=0} \\ 0+3y\leq6 \\ y\leq2 \\ First\text{ point\lparen0,2\rparen} \end{gathered}\begin{gathered} We\text{ find the x-intercept by setting y=0} \\ x+3(0)\leq6 \\ x\leq6 \\ Secon\text{d point;\lparen6,0\rparen} \end{gathered}

So by finding the x-intercept and y-intercept, we can determine where to draw the line. Since the inequality is greater than or equal to the line will be continuous and not broken. Also, we will know the area we will shade by;

\begin{gathered} Resolving\text{ the inequality and make y the subject of the formular} \\ x+3y\leq6 \\ 3y\leq6-x \\ y\leq2-\frac{x}{3} \end{gathered}

Since if we set x=0, we get y < or equal to 2, then we know that the shaded area will be where y is equal to and below. There we will shade below the point (0,2) to represent the solution set.

8 0
1 year ago
In the diagram below, you are given that ∠AVD = ∠BVE = ∠CVF= 90° and ∠CVD = 22°. If ∠AVB= ∠EVF, how many degrees are in the meas
lana66690 [7]

Answer:

m∠AVF = 158°

Step-by-step explanation:

In the diagram attached,

m∠AVD = m∠BVE = m∠CVF = 90°

m∠CVD = 22°

∠AVB = ∠EVF

Since ∠AVD = ∠AVC + ∠CVD

Therefore, 90° = m∠AVC + 22°

m∠AVC = 90° - 22°

             = 68°

Similarly, m∠CVF = m∠CVD + m∠DVF

90° = 22° + m∠DVF

m∠DVF = 68°

m∠AVC = m∠DVF = 68°

Now ∠AVF = ∠AVD + ∠DVF

                  = 90° + 68°

                  = 158°

3 0
3 years ago
What is the equation?
klasskru [66]

Answer:

f(x) = 2(x + 3)²

Step-by-step explanation:

Parent Graph: f(x) = a(bx - h)² + k

<em>a</em> is vertical shrink/stretch

<em>b</em> is horizontal shrink/stretch

<em>h</em> is horizontal movement left/right

<em>k</em> is vertical movement up/down

<em>h, k</em> is vertex

Step 1: Define variables

h = -3

k = 0

a = 2

Step 2: Write quadratic

f(x) = 2(x + 3)²

7 0
4 years ago
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