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1 year ago

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Mathematics

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andrew-mc [135]1 year ago

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The prediction for average temperature is 53.06° F

Given: The equation for line of best fit:

y = -3.32x + 97.05

What is line of best fit?

Line of best fit is the line that is drawn through the points and it minimizes the error between the actual data and the predicted data.

In a regression graph, there are many scattered points and it becomes very difficult to predict a general equal if we focus on the coordinates and relations of each points. The line of best fit, is a line that passes through the center or from a position where the error between the point and the line is the minimum and it becomes easy to predict or a derive an equation or a relation.

What is a response variable?

A response variable is a variable that is dependent on one or more independent or dependent variables for it's value. So let's say in this equation y = mx + c, y is the response variable as on the change of variable x , y will have different values that is y will response differently for different values of x. Hence y is the dependent variable.

What is predictor variable?

A predictor variable is a variable that is independent of the influence from any other variable, and a change in this variable will give different outcomes. It is called predictor because or a change in it's value we can predict an outcome.

Let's solve the question that is given:

Now y is the response variable and x is the predictor variable.

From the given graph, we see

x = inches of rain

y = average temperature

To make the prediction for x = 13.25, we place the value of x in the equation of line of best fit, that is:

y(13.25) = -3.32*13.25 + 97.05 = 53.06

Hence our prediction or the response for average temperature is 53.06° F

Know more on "line of best fit" here: brainly.com/question/14279419

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Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec

german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

Let's start with sin here. $\frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}}$ Therefore, because sin is y/r, r = $\sqrt{5}$ and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = $\frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}$

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = $4\sqrt{2}$ . Now, to find csc, we have to do r/y.

csc = $\frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}$

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = $\sqrt{7/16}$ = $\frac{\sqrt{7}}{4}$

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = - $\sqrt{7/9} = \frac{-\sqrt{7}}{3}$

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = $(\frac{-\sqrt{6}}{2})^{2}$

1 + cot^2 = 6/4

cot^2 = 2/4

cot = $\frac{\sqrt{2}}{2}$

tan = $\sqrt{2}$

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

$(\frac{2}{\sqrt{2}})^2$ + 1 = sec^2