Question

For the function, evaluate the given expression. f(x, y) = 139 − x2 − y2. Find f(3, −9).

Answer 1

The value of the expression f(x,y)=139-$x^{2} -y^{2}$ at (3,-9) is 49.

Given that the expression is  f(x,y)=139-$x^{2} -y^{2}$ and point (3,-9).

We are required to find the value of the expression f(x,y)=139-$x^{2} -y^{2}$ at (3,-9).

Expression is basically a combination of numbers, fractions, symbols, coefficients,determinants,indeterminants. They are mostly not found in equal to form.

Expression is f(x,y)=139-$x^{2} -y^{2}$.

To find the value of expression f(x,y) at (3,-9).

f(3,-9)=139-$(3)^{2} -(9)^{2}$ (Squaring 3 and -9)

f(3,-9)=139-9-81   (Now add 9 and 81 and put minus sign before the result)

f(3,-9)=139-90    

f(3,-9)=49            (Now subtract 90 from 139)

Hence the value of the expression f(x,y)=139-$x^{2} -y^{2}$ at (3,-9) is 49.

Learn more about expressions at brainly.com/question/723406

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