For f(x) to be a function, the value of x should not be repeated. That is no x value can be more then once.
So the required table is
And for g(x) , not to be a function, we have to repeat x value that is
Answer:
There is no mode.
Step-by-step explanation:
Be sure to put in there is no mode, don't put in zero. If you put in zero, it will seem like ) is the mode, you know what I mean.
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Answer:
The first term is 3. The common difference is 2.
Step-by-step explanation:
The first term is x.
The common difference is d.
The second term is x + d.
3rd term: x + 2d
4th term: x + 3d
7th term: x + 6d
"The fourth term of an Arithmetic Sequence is equal to 3 times the first term"
x + 3d = 3 * x Eq. 1
"the seventh term exceeds twice the third term by 1"
x + 6d = 2(x + 2d) + 1 Eq. 2
Simplify Eq. 1:
2x = 3d
Simplify Eq. 2:
x + 6d = 2x + 4d + 1
x = 2d - 1
Multiply both sides of the last equation by 2.
2x = 4d - 2
2x = 3d (simplified Eq. 1)
Since 2x = 2x, then the right sides are equal.
3d = 4d - 2
d = 2
2x = 3d
2x = 3(2)
2x = 6
x = 3
Answer: The first term is 3. The common difference is 2.
Answer:
Dalton spent 6 years and 11 months in high school.
Step-by-step explanation:
Dalton were in high school at the age = 11 years and 3 months He left high school at the age = 18 years and 2 months
Time spent by Dalton in high school = 18 years 2 months - 11 years and 3 months
= (18 - 11) years and (2 - 3) months
= 7 years - 1 month
= (6 + 1) years - 1 month
= 6 years + 1 year - 1 month
= 6years + 12 months - 1 month
= 6 years + 11 months
Therefore, Dalton spent 6 years and 11 months in high school.
8775
/ \
3 2925
/ \
3 975
/ \
3 325
/ \
5 65
/ \
5 13
/ \
13 1
Prime Factors: 3, 3, 3, 5, 5, 13
