Question

How does the mean absolute deviation (mad) of the data in set 1 compare to the mean absolute deviation of the data in set 2? set 1: 12, 8, 10, 50 set 2: 13, 9, 8 the mad of set 1 is 13 less than the mad of set 2. the mad of set 1 is 13 more than the mad of set 2. the mad of set 1 is 2 more than the mad of set 2. the mad of set 1 is 2 less than the mad of set 2.

Answer 1

The Mean Absolute Deviation of Set 1 exists 13 more than the mean absolute deviation of Set 2.

How to estimate the Mean Absolute Deviation from the given data?

Set 1: 12, 8, 10, 50

Set 2: 13, 9,8

To determine the mean for each set

Mean = totality of elements/number of elements

Mean of Set 1:

$=\frac{12+8+10+50}{4}$

$=\frac{80}{4}=20$

Mean of Set 2:

$=\frac{13+9+8}{3}$

$=\frac{30}{3}=10$

To determine the mean absolute deviation (MAD) of the data in each set.

M.A.D of Set 1:

$=\frac{|12-20|+|8-20|+|10-20|+|50-20|}{4}$

$=\frac{8+12+10+30}{4}=\frac{60}{4}=15$

M.A.D of Set 2:

$=\frac{|13-10|+|9-10|+|8-10|}{3}$

$=\frac{3+1+2}{3}=\frac{6}{3}=2$

The Mean Absolute Deviation of Set 1 exists 13 more than the mean absolute deviation of Set 2.

To learn more about Mean Absolute Deviation refer to:

brainly.com/question/447169

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