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Soloha48 [4]
2 years ago
5

Write 3% two different ways. Explain how you know this.

Mathematics
1 answer:
Marysya12 [62]2 years ago
3 0

Answer:

0.03

3/100

Step-by-step explanation:

because 3 percent of a hundred can be written as a fraction and 3 percent is three one hundreths which can be written as a decimal.

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Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.
katrin [286]

x=5.38 . Correct option C)5.38

<u>Step-by-step explanation:</u>

Here we have , Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.  picture is attached  . Let's find out:

In the given figure , Let's draw a line from center to the point where cord of length 8 unit is touching the circle or intersecting or , where this chord finishes . This line is radius of circle and is denoted by x , So now we have a right angle triangle with dimensions as :

Perpendicular =3.6\\Base=\frac{8}{2}=4\\Hypotenuse=x

By Pythagoras Theorem ,

Hypotenuse^2=Perpendicular^2+base^2

⇒ x^2=(3.6)^2+(4)^2

⇒ x=\sqrt{(3.6)^2+(4)^2}

⇒ x=\sqrt{12.96+16}

⇒ x=\sqrt{28.96}

⇒ x=5.38

Therefore , x=5.38 . Correct option C)5.38

6 0
3 years ago
Kelli is walking to raise money for a local shelter. A neighbor gives her $20. Her uncle donates $2 per kilometer. Write an equa
stiv31 [10]
Y=20+2x I think this is right
4 0
2 years ago
Not sure how to find what x equals
Llana [10]

Answer:

Its 48 °

Since its a triangle, the total angle will be 180°

So,

x° + 42°+90°=180°(90° as one angle in triangle is 90°)

x°=180°-90°-42°

x°=48°

7 0
2 years ago
Read 2 more answers
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
Helpppppppppppppppppppppppppppppp
3241004551 [841]
Answer:

first option: Harulo is correct because the angle is coterminal with 3π / 4 and the reference angle is π / 4.

Explanation:

1) 19 π/4 = 4π + 3 π/4, which is 4 complete turns and 3/4 of turn.

2) 3 π/4 is in the third quadrant, so the reference angle is π - 3 π/4 = π/4

3) sin (π/4) = sin (3π/4) = (√2) / 2

4) csc (π/4) =  1 / [ sin (3π/4) ] = 1 / [ (√2) / 2 ] = 2 / (√2) = √2, which shows the validity of the statement and csc(19π/4) = √2.
3 0
3 years ago
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