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never [62]
1 year ago
9

What all can you tell me about this shape?

Mathematics
2 answers:
noname [10]1 year ago
8 0

Answer: It is an equilateral square

Step-by-step explanation: it has 4 tick marks

wel1 year ago
5 0
It is an equilateral square.
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HELPPPPPP I REALLLY NEED THIS DONE!!!! ILL MARK YOU AS BRAINIEST!!!!
sashaice [31]

Answer:

The mad for this graph is 23 hope it helped!

Step-by-step explanation:

8 0
3 years ago
What is the measure of x? Please help!
Zepler [3.9K]

Answer:

x =√[y²+(27)²] = √[ z² - 3² +(27)²]

Step-by-step explanation:

step 1) x=√[y²+(27)²]

step 2)

We find y

z²=y²+3² → y² = z² - 3²

step 3) x = √[ z² - 3² +(27)²]

7 0
3 years ago
Write an equivalent expression for the following by combining like terms: 4y − y + 7y
Assoli18 [71]
4y - y + 7y

4y - y = 3y

3y + 7y = 10y

10y is your answer

hope this helps
4 0
3 years ago
X<br> ſocm<br> Jicm<br> A) 2V5 cm<br> B) V13 cm<br> D) V19 cm<br> C) 1 cm<br> ASAP
bulgar [2K]

Answer:

using pythagoras theorem

hyp 2=opp 2+adj 2

=( √6)(√6)+(√7)(√7)

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3 0
3 years ago
Read 2 more answers
Given that f(a+b)= f(a) + f(b) and f(x) is always positive, what os the value of f(0)?
FrozenT [24]
This is a strange question, and f(x) may not even exist. Why do I say that? Well..

[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).

[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!

Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.

To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
4 0
3 years ago
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