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enot [183]
3 years ago
13

Write the equation of a line in y = mx + b form that has a slope of 7/3 and a y-intercept of 2.

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

Answer:

y = 7/3 x + 2

Step-by-step explanation:

y = mx+b is the slope intercept form of a line

where m is the slope and b is the y intercept

Substituting in what we know

y = 7/3 x + 2

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✨ B R A I N L I E S T
miv72 [106K]

1

:x

2

+y

2

−6x−9y+13=0

(x−3)

2

+(y−

2

9

)

2

−9−

4

81

+13=0

(x−3)

2

+(y−

2

9

)

2

=

4

65

Here,

r

1

=

2

65

C

1

=(3,

2

9

)

Equation of another circle-

S

2

:x

2

+y

2

−2x−16y=0

(x−1)

2

+(y−8)

2

−1−64=0

(x−1)

2

+(y−8)

2

=65

Here,

r

2

=

65

C

2

=(1,8)

Distance between the centre of two circles-

C

1

C

2

=

(3−1)

2

+(8−

2

9

)

2

C

1

C

2

=

4+

4

49

=

2

65

∣r

2

−r

1

∣=

∣

∣

∣

∣

∣

∣

65

−

2

65

∣

∣

∣

∣

∣

∣

=

2

65

∵C

1

C

2

=∣r

1

−r

2

∣

Thus the two circles touches each other internally.

Since the circle touches each other internally. The point of contact P divides C

1

C

2

externally in the ratio r

1

:r

2

, i.e.,

2

65

:

65

=1:2

Therefore, coordinates of P are-

⎝

⎜

⎜

⎜

⎜

⎜

⎛

1−2

1(1)−2(3)

,

1−2

1(8)−2(

2

9

)

⎠

⎟

⎟

⎟

⎟

⎟

⎞

=(5,1)

Therefore,

Equation of common tangent is-

S

1

−S

2

=0

(5x+y−6(

2

x+5

)−9(

2

y+1

)+13)−(5x+y−2(

2

x+5

)−16(

2

y+1

))=0

2

−6x−9y−13

+x+8y+13=0

4x−7y−13=0

Hence the point of contact is (5,1) and the equation of common tangent is 4x−7y−13=0.

4 0
3 years ago
Read 2 more answers
Divide 3m 80cm of ribbon in the ratio of 1/3 : 3/4 : 1/2 what is the result?​
JulijaS [17]

Answer:

80 cm / 180 cm / 120 cm

Step-by-step explanation:

the smallest common multiple of 3, 4 and 2 is 12.

so, to be able to truly compare these fractions we need to bring all denominators to .../12.

1/3 = 4/12

3/4 = 9/12

1/2 = 6/12

in total we have therefore 19 (4+9+6) equally large parts of the ribbon that are then combined :

4 parts for the first segment.

9 parts for the second segment

6 parts for the third segment.

so, one part is

380 cm / 19 = 20 cm

therefore the first segment of the ribbon is

4×20 = 80 cm long

the second segment

9×20 = 180 cm long

the third segment

6×20 = 120 cm long

4 0
3 years ago
Answer the following: GCF of 20 & 32 GCF of 45 & 75
Jet001 [13]

Answer:

GCF OF 20 AND 32: 4

Gcf of 45 and 75: 15

Step-by-step explanation:

GcF of 20 and 32

Factors of 20: 1, 2, 4, 5, 10, 20

Factors of 32: 1, 2, 4, 8, 16, 32

COMMON FACTORS: 1, 2, 4

GCF:4

Gcf of 45 and 75

Factors of 45: 15, 9, 5, 3, 1.

Factors of 75: 25, 15, 5, 3, 1.

CommoN factors: 1, 3, 5, 15

GCF:15

HOPE OT HELPED

3 0
3 years ago
Read 2 more answers
5) Coach Koehler bought supper for all the participating volleyball players after the tournament. The food was ordered from Food
Musya8 [376]

Answer:

25 hamburger

20 hot dogs

Step-by-step explanation:

7 0
3 years ago
Consider the equation n2+5=21.
lesya692 [45]

Step-by-step explanation:

n2+5=21

n2 =21-5

n2 = 16

n =16/2=8

6 0
3 years ago
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