Find the mean and standard deviation for the set of data.
1 answer:
The mean and standard deviation for the set of data will be 16 and 5.87. Then the correct option is A.
<h3>What is a standard deviation?</h3>It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.
The set of data is given below.
16, 22, 8, 5, 20, 18, 14, 17, 24
The mean of the data set will be
μ = (16 + 22 + 8 + 5 + 20 + 18 + 14 + 17 + 24) / 9
μ = 144 / 9
μ = 16
Then the standard deviation of the data set will be
Simplify the expression further, then we have
σ = √34.44
σ = 5.87
The mean and standard deviation for the set of data will be 16 and 5.87.
Then the correct option is A.
More about the standard deviation link is given below.
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Answer:
Step-by-step explanation:
In order to write the series using the summation notation, first we need to find the nth term of the sequence formed. The sequence generated by the series is an arithmetic sequence as shown;
4, 8, 12, 16, 20...80
The nth term of an arithmetic sequence is expressed as Tn = a +(n-1)d
a is the first term = 4
d is the common difference = 21-8 = 8-4 = 4
n is the number of terms
On substituting, Tn = 4+(n-1)4
Tn = 4+4n-4
Tn = 4n
The nth term of the series is 4n.
Since the last term is 80, L = 4n
80 = 4n
n = 80/4
n = 20
This shows that the total number of terms in the sequence is 20
According to the series given 4 + 8 + 12 + 16 + 20+ . . . + 80 , we are to take the sum of the first 20terms of the sequence. Using summation notation;
4 + 8 + 12 + 16 + 20+ . . . + 80 =