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Xelga [282]
3 years ago
9

See question above 7.2 cm 9 cm 10.6 cm 12 cm

Mathematics
1 answer:
alukav5142 [94]3 years ago
3 0
Um what’s the question?
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2^3a^7 times 2a^3 NEEE HELP​
hichkok12 [17]

Step-by-step explanation:

explain step by step on photo, double check just in case

6 0
3 years ago
{2x + 3y = 5}{ y= 5 x -4}
Natasha_Volkova [10]

Solve the system using substitutions:

\begin{gathered} 2x+3y=5 \\ 2x+3(5x-4)=5 \\ 2x+15x-12=5 \\ 17x=5+12 \\ 17x=17 \\ x=\frac{17}{17} \\ x=1 \end{gathered}

x has a value of 1. Use this value to find the value of y.

\begin{gathered} y=5x-4 \\ y=5\cdot1-4 \\ y=5-4 \\ y=1 \end{gathered}

y has a value of 1.

x=1

y=1

8 0
1 year ago
1728829+5363792002×82873992892/12=?​
son4ous [18]

Answer:

Simplify the expression.

Exact Form:

111129715061983798933/3

Decimal Form:

3.70432383⋅10^19

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The slope of the line containing the points (-2,3) and (-3,1) is
Irina18 [472]

To calculate the slope containing two points, we can use that formula:


\mathsf{m=\dfrac{y_2-y_1}{x_2-x_1}}


"m" represents the slope and coordinates are expressed as follows: (x, y)


Let's go to the calculations.


\mathsf{m=\dfrac{y_2-y_1}{x_2-x_1}}\\\\\\ \mathsf{m=\dfrac{1-3}{-3-(-2)}}\\\\\\ \mathsf{m=\dfrac{-2}{-3+2}}\\\\\\ \mathsf{m=\dfrac{-2}{-1}}\\\\\\ \mathsf{m=\dfrac{2}{1}}\\\\\\ \underline{\mathsf{m=2}}


The answer is 2 uc.

5 0
2 years ago
Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.8. (Round your ans
Alenkinab [10]

Answer:

a) 0.011 = 1.1% probability that the sample mean hardness for a random sample of 17 pins is at least 51

b) 0.0001 = 0.1% probability that the sample mean hardness for a random sample of 45 pins is at least 51

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 50, \sigma = 1.8

(a) If the distribution is normal, what is the probability that the sample mean hardness for a random sample of 17 pins is at least 51?

Here n = 17, s = \frac{1.8}{\sqrt{17}} = 0.4366

This probability is 1 subtracted by the pvalue of Z when X = 51. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{51 - 50}{0.4366}

Z = 2.29

Z = 2.29 has a pvalue of 0.9890

1 - 0.989 = 0.011

0.011 = 1.1% probability that the sample mean hardness for a random sample of 17 pins is at least 51

(b) What is the (approximate) probability that the sample mean hardness for a random sample of 45 pins is at least 51?

Here n = 17, s = \frac{1.8}{\sqrt{45}} = 0.2683

Z = \frac{X - \mu}{s}

Z = \frac{51 - 50}{0.0.2683}

Z = 3.73

Z = 3.73 has a pvalue of 0.9999

1 - 0.9999 = 0.0001

0.0001 = 0.1% probability that the sample mean hardness for a random sample of 45 pins is at least 51

8 0
3 years ago
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