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dem82 [27]
2 years ago
13

An employer provides two payment options for employees.

Mathematics
1 answer:
mixer [17]2 years ago
4 0
<h2>Option A</h2>

a_n = a_1 + (n - 1)d \\ a_n = 200 + 50(n - 1) \\ a_2 = 200 + 50(2 - 1)  = 250\\ a_3 = 200 + 50(3 - 1) = 300 \:  \\ a_4 = 200 + 50(4 - 1) = 350 \\ a_5 = 200 + 50(5 - 1) = 400 \\ a_6 = 200 + 50(6 - 1) = 450

<h2>Option B</h2>

\:  \: u_{n } = 200(1 + 0.1) {}^{n - 1}  \\ u_{n } = 200(1.1) {}^{n - 1}  \\

u_1 = 200(1.1) {}^{1 - 1}  = 200 \\ u_2 = 200(1.1) {}^{2 - 1}  = 220  \\ u_3 = 200(1.1) {}^{3 - 1}  = 242 \\ u_4 = 200(1.1) {}^{4 - 1}  = 266.2 \\ u_5 = 200(1.1) {}^{5 - 1}  = 292.82 \\ u_6 = 200(1.1) {}^{6 - 1}  = 322.102

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