Question

An employer provides two payment options for employees.

Answer 1

Option A

$a_n = a_1 + (n - 1)d \\ a_n = 200 + 50(n - 1) \\ a_2 = 200 + 50(2 - 1) = 250\\ a_3 = 200 + 50(3 - 1) = 300 \: \\ a_4 = 200 + 50(4 - 1) = 350 \\ a_5 = 200 + 50(5 - 1) = 400 \\ a_6 = 200 + 50(6 - 1) = 450$

Option B

$\: \: u_{n } = 200(1 + 0.1) {}^{n - 1} \\ u_{n } = 200(1.1) {}^{n - 1}$

$u_1 = 200(1.1) {}^{1 - 1} = 200 \\ u_2 = 200(1.1) {}^{2 - 1} = 220 \\ u_3 = 200(1.1) {}^{3 - 1} = 242 \\ u_4 = 200(1.1) {}^{4 - 1} = 266.2 \\ u_5 = 200(1.1) {}^{5 - 1} = 292.82 \\ u_6 = 200(1.1) {}^{6 - 1} = 322.102$