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1 year ago

8

Two trains leave towns 664 miles apart at the same time and travel toward each other. One train travels 16 mih faster than the o

ther. If they meet in 4 hours, what is the rate of each train?

1 answer:

Hatshy [7]1 year ago

5 0

Answer:

I think that I am right. One train is traveling at 75 mph and the other train is traveling at 91 mph

Step-by-step explanation:

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3 years ago

Tju [1.3M]

Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by $\sqrt{x}$

$b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x} }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\$

Now, find a +b

$a +b = \frac{2x+\sqrt{x} }{x}+\frac{\sqrt{x} -2x}{x}\\\\=\frac{2x+\sqrt{x} +\sqrt{x} -2x}{x}$

Combine like terms

$= \frac{2x-2x+\sqrt{x} +\sqrt{x} }{x}\\\\=\frac{2\sqrt{x} }{x}$

Now find (a + b)²

(a +b)² = $(\frac{2\sqrt{x} }{x})^{2}$

$= \frac{2^{2}*(\sqrt{x} )^{2}}{x^{2}}\\\\= \frac{4* x}{x^{2}}\\\\= \frac{4}{x}$

Hint: $\sqrt{x} *\sqrt{x} =\sqrt{x*x}=x$

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3 years ago

Use the following rules to graph and label the ordered pairs on a coordinate grid with at least 4 points on the coordinate plane

Sati [7]

Answer:

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Step-by-step explanation:

I just had this question

3 0

2 years ago

Can someone please help me in this question.

mestny [16]

Answer:

a) $2^{3}$

b) $2^{5}$

c) $2^{8}$

d) $\frac{5}{2^{3} }$

e) $2^{4} + 2^{3}$

Step-by-step explanation:

a) 8 = 2 x 2 x 2

b) 32 = 2 x 2 x 2 x 2 x 2

c) 256 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

d) 5 x 2^3 / 64 = 5 x 8 / 64

= 40/64

= 5/8

= $\frac{5}{2^{3} }$

e) 16 - (-2)^3 = 16 - (-8)

= 16 + 8

= $2^{4} + 2^{3}$

6 0

3 years ago