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3 years ago

The shortest path from a starting point to an endpoint, regardless of the path taken, is called the _____________.

2 answers:

7 0

<span>The shortest path from a starting point to an endpoint, regardless of the path taken, is called the </span>geodesic. In flat (Euclidean) space it is simply a straight line.

WITCHER [35]3 years ago

6 0

It is called the displacement, since it is the shortest path between two given points.

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1. Mervin Moneybags went on a spending spree today. He spent half of his money on à Slammy So-so baseball card. He spent $50 on

Artist 52 [7]

Answer:

$150

Step-by-step explanation:

50+25=75

since he spent another half 75 is the other half

so 75+75

150

8 0

2 years ago

solve 6/x -4 = 4/x for x and determine if the solution is extraneous or not. x = −8, extraneous x = −8, non-extraneous x = 8, ex

disa [49]

$\frac{6}{x-4} = \frac{4}{x} \\ 6x=4(x-4)=4x-16 \\ 2x=-16 \\ x=-8$
To check: 6/(-8-4) = 4/-8
6/-12 = 4/-8
1/-2 = 1/-2
Therefore, <span>x = −8, non-extraneous</span>

5 0

3 years ago

What is the slope and y-intercept for the line represented by this equation? -3x+8y= -24

salantis [7]

I believe its a -3...............

5 0

3 years ago

Read 2 more answers

A point particle with charge q is at the center of a Gaussian surface in the form of a cube. The electric flux through any one f

TEA [102]

Answer:

iv. q/6E0

Step-by-step explanation:

Electric flux formula:

The electic flux formula, of a charge q is given by, through an entire cube, is given by:

$E = \frac{q}{E_o}$

In which $E_o$ is a constant related to the material.

The electric flux through any one face of the cube is:

Key-word is face, and a cube has 6 faces, with the force distributed evenly throughout it. Thus

$E_f = \frac{1}{6} \times \frac{q}{E_o} = \frac{q}{6E_o}$

And the correct answer is given by option iv.

8 0

3 years ago

Find either the maximum or the minimum value of the following quadratic equation. Be sure to show all of your work and identify

podryga [215]

Answer:

the minimum is (1,-9)

Step-by-step explanation:

y = 5x^2 - 10x - 4

since the parabola opens upward 5>0, this will have a minimum

it will occur along the axis of symmetry h=-b/2a

y =ax^2 +bx+c

h = -(-10)/2*5

h = 10/10 =1

the minimum occurs at x =1

the y value for the minimum is calculated by substituting x =1 back into the equation

y = 5 * 1^2 - 10*1 -4

y = 5*1^2 -10 -4

y = 5-10-4

y = -9

the minimum is (1,-9)

6 0

3 years ago