Which of these nets will not form closed cubes?

How do I do kcf in math

juin [17]

Um well KCF stands for Keep Change Flip which is used for dividing fractions... ask if you need a better description ☺️

7 0

3 years ago

Help me solve this I wil give brainliest and 40 points

Verizon [17]

Answer:

Slope: $-\dfrac{1}{2}$

Equation: $y=-\dfrac{1}{2}x+8$

Step-by-step explanation:

The line of the best fit passes through the points (0,8) and (4,6).

If the line passes through the points $(x_1,y_1)$ and $(x_2,y_2)$ then the slope of the line is

$\dfrac{y_2-y_1}{x_2-x_1}$

Hence, the slope of the line of the best fit is

$\dfrac{6-8}{4-0}=\dfrac{-2}{4}=-\dfrac{1}{2}$

The equation of the line is

$y=mx+b,$

where m is the slope and b is y-intercept, so the equation of the line of the best fit is

$y=-\dfrac{1}{2}x+8$

4 0

3 years ago

What is the value of a in the right triangle shown below?

notka56 [123]

I think you forgot to show the right triangle because there is no image I would like to help you if you post the picture

3 0

3 years ago

The elementary school lunch menu repeats every 20 days ; the middle school lunch menu repeats every 15 days. Both schools are se

Vikki [24]

The trick to this question is the find the least common multiple of 20 and 15. You could do 20×3=60 and 15×4=60 as those both equal the same number yet you there are no other multiples they share before 60. So the next time the two schools will eat pizza on the same day again will be in 60 days. Hope this helps!

7 0

4 years ago

Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t

katrin2010 [14]

Answer:

$\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24$

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of $\triangle ACD$ and the hypotenuse of $\triangle ADB$ .

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

$\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}$

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is $\angle CAD$ . The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

$\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}$

Now use this value in the Law of Sines to find AD:

$\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}$

Recall that $\sin 45^{\circ}=\frac{\sqrt{2}}{2}$ and $\sin 60^{\circ}=\frac{\sqrt{3}}{2}$ :

$AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}$

Now that we have the length of AD, we can find the length of AB. The right triangle $\triangle ADB$ is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio $x:x\sqrt{3}:2x$ , where $x$ is the side opposite to the 30 degree angle and $2x$ is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent $2x$ in this ratio and since AB is the side opposite to the 30 degree angle, it must represent $x$ in this ratio (Derive from basic trig for a right triangle and $\sin 30^{\circ}=\frac{1}{2}$ ).

Therefore, AB must be exactly half of AD:

$AB=\frac{1}{2}AD,\\AB=\frac{1}{2}\cdot 50\sqrt{6},\\AB=\frac{50\sqrt{6}}{2}=\boxed{25\sqrt{6}}\approx 61.24$

3 0

3 years ago

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