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3 years ago

What is the value of (-14)-2

Mathematics

2 answers:

AleksandrR [38]3 years ago

5 0

If you subtract 2 from -14 you will get -16. The answer is -16

ryzh [129]3 years ago

3 0

Answer:

-16 is correct answer

Step-by-step explanation:

$( - 14) - 2 \\ = - 16$

hope it helped you:)

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Solve the equation for the variable, show your work 11x - 16 = -49 x = _____

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

<h2>Given,</h2>

11x - 16 = -49

=> 11x = - 49 + 16

=> 11x = -33

$= > x = \frac{ - 33}{11}$

=> x = -3 (Ans)

5 0

3 years ago

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Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Solution:

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

3 years ago

Simplify completely: 4V10 – V6 +3710 Show all work for full credit.

schepotkina [342]

The answer is 7√10−√6

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3 years ago

If y varies inversely as x and y=32 when x=3, find x when y=15

deff fn [24]

Y=kx, k is not equal to 0
when y=32,x=3, 32=3k
k=32/3
so y=32/3*x
when y=15, 15=32/3*x
x=45/32

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4 years ago

If you are able to save, $150 dollars per month-how many months will it take you to

Katen [24]

Answer:

16.66months

Step-by-step explanation:

2500/150

6 0

3 years ago

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