Answer:
y=-
x+
Step-by-step explanation:
First, calculate the slope of the line that is perpendicular to the equation of line we are asked to find
m=(y2-y1)/(x2-x1)
=(2-(-4))/(-2-1)
=6/-3
=-2
in this equation the slope is 2, and to find the first equation, use y=mx+b
use the point (1, -4) to find b
-4=(2)(1)+b
-4=2+b
b=-6
the first equation of the line is y=2x-6
to find the x intercept of that line substitute 0 for y
0=2x-6
2x=6
x=3
the slope of a line perpendicular to this would be the opposite reciprocal of the slope which would be equal to -1/2
for the second equation of the line to pass thorugh the x-intercept of the first line, it must pass through (3, 0), so substitute and solve for b
y=mx+b
0=(-1/2)(3)+b
b=3/2
thus the equation of the line that is perpendicular to the line through (1,-4) and (-2, 2) and passes through the x intercept of that line is y=-
x+3/2
Answer:
19.80
Step-by-step explanation:
use the is/of x %/100 method.
33/100 x x/60
1980/100x = 19.80$
The answer is If you would like to find the expression that is equivalent to (t*s)(x), you can calculate this using the following steps:
s(x) = x - 7
t(x) = 4x^2 - x + 3
(t*s)(x) = t(s(x)) = t(x - 7) = <span>4(x - 7)^2 - (x - 7) + 3 = 4(x - 7)^2 - x + 7 + 3
The correct result would be </span>4(x – 7)2 – (x – 7) + 3.
Answer:
The degree of the given polynomial is 3.
Hope it will help :)