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Zolol [24]
3 years ago
7

1. A drawer contains 6 red socks in a total of 10 socks. What is the probability of selecting a red sock?

Mathematics
1 answer:
Vlad1618 [11]3 years ago
4 0

Answer:

60% since 6/10 = 0.6 = 60%

2/11 = 18.1818182 percent (its infinite 18's)

3/22 = 13.6363636%

50% since 1,2,3,4,5,6 the odds are 3 odd and 3 even so 1 to 1 so 50% or 3/6

100% since 15/15 = 100

50% since 4/8 = 50%

1/3 or 33% since 1/3 as a decimal is .33333333 infinite

2/9 = 22.22222%

A. 25% or 1/4

B. 7.70% rounded to the tenth or 1/13

C. 7.70 since it is still 4 kings and 4 fours. so still 1/13

D. 25% since there are 4 suits. so once again 1/13

N chance. 2/20=10%

A chance. 10% since there is 2 A's again

G chance. 1/20 x 5 = 5/100 = 5%

Vowel 7/20 = 35%

Extension

1/2 What is the probability of getting heads on a coin?

0% What is the chance of getting 1 girl in a class with 0 girls and 20 boys.

1 or 100 percent? Im doing both

1. What is the chance of selecting a penny in 25 quarters, 24 nickels, 25 dimes, and 1 penny? That is the 1 percent

100 percent. What is the chance of flipping either heads or tails on a coin?

D. 2/7 There are 7 coins in total. There are 2 pennies, 3 quarters, and 2 dimes what is the chance of a dime?

If you have any questions you can ask hope this helps! Check the grammar in case i made any mistakes

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Step-by-step explanation:

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A set of data included the numbers 19, 81, 75, 42, 33 57, and 60. What number could be added to the data to cause the range to b
dsp73

Answer:

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Step-by-step explanation:

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3 years ago
FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM
algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , thus

S_{20} = \frac{20}{2} [ (2 × - 1) + (19 × 4) ]

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3 years ago
PLEASE HELP!!!!! DUE TODAY!!!
Akimi4 [234]

Answer:

5

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Rental = $40

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Budget = $100

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= $60

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= 5

5 0
3 years ago
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