Find the VERTEX of the parabola f(x) = x^2 - 16x + 63
1 answer:
Answer:
vertex = (8, - 1 )
Step-by-step explanation:
Given a parabola in standard form, f(x) = ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= -
f(x) = x² - 16x + 63 ← is in standard form
with a = 1 and b = - 16, thus
= -
= 8
Substitute x = 8 into f(x)
f(8) = 8² - 16(8) + 63 = 64 - 128 + 63 = - 1
vertex = (8, - 1 )
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