Answer:
0.00508368 grams
Explanation:
From the question we are told that the daily allowance for infants and children is 8.00 × 10⁻⁶ mole of copper per kiogram of body weight.
Since this value is given in moles, we have to convert it to mass
Molar mass of a compound = mass in grams / no of moles of the compound.
So, Molar mass of copper = 63.546
No of moles of copper per kg = 8.00 × 10⁻⁶ mole
63.546 = mass/ 8.00 × 10⁻⁶ mole
Cross multiply
Mass of copper per kg body weight = 8.00 × 10⁻⁶ × 63.546
= 0.000508368 grams
Hence, the daily allowance of copper required for infants or children per kg of weight = 0.000508368 grams.
For a 10 kg infant this is calculated as:
If 1 kg per weight of an Infant = 0.000508368grams
10 kg =
We cross multiply
10 kg × 0.000508368 grams
= 0.00508368 grams.
Therefore, the mass of copper required per day for a 10 kg child is 0.00508368 grams
