<span>Here let the quadratic equation be ax^2 + bx + c
We know that a=5 from the question.
Since the roots are 6 and 2, the quadratic equation would take the form of a product like (a1x-b1)(a2x-b2).
However, let's assume that a2=1 and b2=6,
Since a=5, a1=5, then 5x-b1=5(x-2). Solving this shows that b1=10
So, the equation is (5x-10)(x-6)</span>
2m: "two multiplied by m"
Answer:
16
Step-by-step explanation:
Dealing with a fraction exponent on hand can be converted by using the fractional exponents rule where the fraction exponent is converted to something like this:
![64^\frac{2}{3} = \sqrt[3]{64^{2}}\\](https://tex.z-dn.net/?f=64%5E%5Cfrac%7B2%7D%7B3%7D%20%3D%20%5Csqrt%5B3%5D%7B64%5E%7B2%7D%7D%5C%5C)
As you can see, the denominator of the fractional exponent is now the index of the radical. Here is a guide to know what goes where.
![64^\frac{x}{y} = \sqrt[y]{64^{x}}](https://tex.z-dn.net/?f=64%5E%5Cfrac%7Bx%7D%7By%7D%20%3D%20%5Csqrt%5By%5D%7B64%5E%7Bx%7D%7D)
Both the original problem (64^2/3) and the converted formula can be put into a calculator.
<u>Simplify (if you want to)</u>
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64 to the power of 2/3 is 16.
Answer:
12 weeks
Step-by-step explanation:
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