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zhannawk [14.2K]
3 years ago
13

Can someone help me find the y-intercept due tomorrow pleasr

Mathematics
1 answer:
Ahat [919]3 years ago
8 0

The first one for the first y-intercept number is -1.

The second one is 5. (Not negative)

The third one is 11 (Not negative)

The fourth one is just 11 (Not negative as well)

The ones that say Not negative means that those numbers are postive.

I hope this helps though! :D

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vesna_86 [32]

Answer:

answer

Step-by-step explanation:

you have to subtract 3b from 3a so the answer is 0.

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Please awnser this asap​
Illusion [34]

Answer:

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3 years ago
Please help me I'm so bad at math and doing AFDA really doesn't help..
Mama L [17]

Answer:

4x²√4√6√x⁶√x

Step-by-step explanation:

4x²√(24x⁷)

The above expression can be simplified as follow:

4x²√(24x⁷)

Recall

√(MN) = √M × √N = √M√N

Thus,

4x²√(24x⁷) = 4x²√24√x⁷

But:

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Therefore,

4x²√(24x⁷) = 4x²√4√6√x⁶√x

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What is the solution for line one: y=-2x+1 line two: -2x-3
Oliga [24]

The slope-intercept form is

y=mx+b

, where m is the slope and b is the y-intercept.

y=mx+b

Find the values of

m

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=

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2

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The slope of the line is the value of

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y-intercept:

(

0

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−

3

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Any line can be graphed using two points. Select two

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x-intercept(s):

(

3

2

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0

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y-intercept(s):

(

0

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−

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Create a table of the

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x

y

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−

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3

2

0

m

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3

2

,

0

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y-intercept(s):

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0

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I'm so sorry it layed out like this my computer is being st00pid

6 0
3 years ago
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If a polynomial has one root in the form a+√b , it has a second root in the form of a_√b
gulaghasi [49]
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.

The first factor is x - (a + √b).
The second factor is x - (a - √b).

The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
      = x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
      = x² - 2ax + x√b - x√b + a² - b
      = x² - 2ax + a² - b

This is a quadratic polynomial, as expected.

If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
   = a +/- (1/2)*√(4b)
   = a +/- √b
x = a + √b, or x = a - √b, as expected.
3 0
3 years ago
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