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3 years ago

10

E sum of negative eighteen and a number is eleven. What is the number?

1 answer:

ololo11 [35]3 years ago

8 0

The missing number is 29

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-1 3/5 divided by -2/3 written as mixed number

blondinia [14]

First, you must change all of this into improper fractions, like shown below.
$- \frac{8}{5}\div - \frac{2}{3} =$
Now you must change the sign.
$- \frac{8}{5}* - \frac{2}{3} =$
Then we must reciprocalize 2/3.
$- \frac{8}{5}* - \frac{3}{2} =$
Now we multiply, to get 2 4/10.

8 0

3 years ago

Which answer shows a correct order to solve this story problem?

OLga [1]

The correct answer would be C :^)

4 0

3 years ago

Read 2 more answers

(x^2–x–4)multiplied by(x–5)

Sergio [31]

$(x-5)(x^2-x-4) =x^3-6x^2+x+20$

Step-by-step explanation:

Given polynomials are:

$x^2-x-4\\and\\x-5$

Both polynomials have to be multiplied. We will use distributive property for the said purpose

So,

$(x-5)(x^2-x-4)\\=x(x^2-x-4)-5(x^2-x-4)\\=x^3-x^2-4x-5x^2+5x+20$

Combining alike terms

$=x^3-x^2-5x^2-4x+5x+20\\=x^3-6x^2+x+20$

Hence,

$(x-5)(x^2-x-4) =x^3-6x^2+x+20$

Keywords: Polynomials, Multiplication

Learn more about polynomials at:

#LearnwithBrainly

7 0

3 years ago

The music festival took 77 days to plan.

liraira [26]

77 days turned into weeks means that you have to divide by seven.
77/7 = 11.
It took eleven weeks to plan (Answer choice D)

8 0

3 years ago

Read 2 more answers

7. The probability that a randomly chosen student will be left-handed is .09: a) In a class of 108, find the probability that th

vampirchik [111]

Solution :

Let x be student will be left handed

P = 0.09

Using the normal approximation to binomial distribution,

a). n = 108,

μ = np = 9.72

$\sigma = \sqrt{np(1-p)}$

$=\sqrt{8.8452}$

= 2.9741

Required probability,

P(x=8) = P(7.5 < x < 8.5)

$=P\left(\frac{7.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{8.5-9.72}{2.9741}\right)$

$=P(-0.75 < z < -0.41)$

Using z table,

= P(z<-0.41)-P(z<-0.75)

= 0.3409-0.2266

= 0.1143

b). P(x=12) = P(11.5 < x < 12.5)

$=P\left(\frac{11.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{12.5-9.72}{2.9741}\right)$

$=P(0.60 < z < 0.94)$

Using z table,

= P(z< 0.94)-P(z< 0.60)

= 0.8294 - 0.7257

= 0.1006

7 0

3 years ago