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Likurg_2 [28]
3 years ago
10

E sum of negative eighteen and a number is eleven. What is the number?

Mathematics
1 answer:
ololo11 [35]3 years ago
8 0
The missing number is 29
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Please solve this for me!!!!
IRINA_888 [86]
323 because I did the quiz and got it right txt me if you need help
6 0
3 years ago
What is tan(θ/2), when tan(θ) = 4/3 and when π < θ < 3π/2?
Tamiku [17]
Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
 then,  Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.

tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]

Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9)        (sec²Ф will have a negative value, because Ф is in the        sec Ф=-5/3                                 third quadrant).

cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5

Therefore:

tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2

Answer: tan (Ф/2)=-2; when tan (Ф)=4/3


3 0
3 years ago
What is 6n-2 when n=3
disa [49]

Answer:

16

Step-by-step explanation:

6n is 6 times 3 if n is 3. 6 times 3 is 18. Minus 2 is 16.

Hope this helps! If it does, please mark me brainliest. Thank you! ;)

4 0
3 years ago
If (1/4)^(x+y) = 256 and log₄(x-y) = 3, what are the exact values of x and y
andrew-mc [135]

Answer:

x = 30 and y = -34

Step-by-step explanation:

Given the following functions

(1/4)^(x+y) = 256... 1

log₄(x-y) = 3.... 2

From equation 2;

x-y = 4³

x-y = 64

x = 64 + y ... 3

Substitutw 3 into 1

From 1:

(1/4)^(x+y) = 256

(1/4)^(64+y+y) = 256

(1/4)^(64+2y) = 256

Take log₄ of both sides

64+2y log₄ (1/4) = log₄256

-(64+2y) = 4log₄4

-(64+2y) = 4

64+2y = -4

2y = -4 - 64

2y = -68

y = -34

Since

x = 64 + y .

x = 64 - 34

x = 30

Hence x = 30 and y = -34

6 0
3 years ago
Please Help!<br> Solve this system of equations <br><br> { 1/2x+6y+2<br> y=x+15
REY [17]

I dont know of you wanted the graph too so here

everything is in the pictures here, also sorry if I am wrong

4 0
3 years ago
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