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ehidna [41]
4 years ago
15

What is the solution for 9 > x - 7?

Mathematics
1 answer:
vodka [1.7K]4 years ago
6 0

Answer:

C

Step-by-step explanation:

9 > x - 7

+7 +7

16 > x

The answer is C.

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I am confused on how to set this question up. Can someone please help me?
gregori [183]

Answer:

Step-by-step explanation:

Comparing triangle EGD and triangle ELA

AL/DG = EL/EG

AL = x, DG = 3, EL = 5+5+5+5= 20

EG = 5

x/3 = 20/5

x/3 = 4

x = 3×4

x = 12

8 0
3 years ago
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What is 9/10 - 11/12
kenny6666 [7]
9/10 - 11/12
Multiply both sides to find a common denominator in this case it’s 60
54/60 - 55/60
Then the answer would be -1/60
3 0
3 years ago
Definition: A word or phrase used to show division in a word problem.
myrzilka [38]
I think the word is "each". im not very sure.


8 0
4 years ago
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The equation for the circle below is x ^2 + y^2 = 100. what is the length of the circles radius?
Ganezh [65]

Answer: 10 units.

Step-by-step explanation:

The equation of the circle in Center-radius form is:

(x - h)^2 + (y - k)^2 = r^2

Where the center is (h,k) and "r" is the radius.

The equation of the circle given is:

x ^2 + y^2 = 100

You can observe that is written in Center-radius form.

Then, you can identify that:

r^2=100

Knowing this, you need to solve for "r" to find the lenght of the radius.

This is:

r=\sqrt{100}\\\\r=10

Therefore, the lenght of the radius is 10 units.

8 0
3 years ago
Can any kind soul help me ASAP!​
CaHeK987 [17]

Answer:

Hope it helps u

Step-by-step explanation:

As we know that ,

Mean = sum of the terms/ numbers of terms

But here grouped data is given so , we use the formula

Mean=∑[f. m]/ ∑f

where f is frequency and m is mid point of each height ,

Now first we have to find the mid point of each interval, where

midpoint of each interval = (lower boundary + upper boundary)/2

m1=(150+154)/2 = 152

m2=(155+159)/2= 157,now found other by same formula, for each interval

m3= 162

m4= 167

m5=172    Now we find the midpoint of each interval ,so now

∑[f. m]=f1*m1+f2*m2+f3*m3+f4*m4+f5*m5

now putting the values of each frequency for given interval and midpoint of each interval we will get,

∑[f. m]=456+942+1296+167*x+344 = 167*x+3038

Now find,

∑f=f1+f2+f3+f4+f5

∑f=19+x

Now we have,

∑[f. m]=167*x+3038

∑f=19+x

also given mean height=161.6 cm

putt these values in above equation we get,

161.6=\frac{167*x+3038}{19+x}

now solve this ,

161.6(19+x)=167*x+3038

3070.4+161.6*x=167*x+3038

3070.4-3038=167*x-161.6*x

32.4=5.4*x

x=32.4/5.4

<h2>x=6   Ans........</h2>

3 0
3 years ago
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